Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
Answer:
The answer to your question is letter C
Step-by-step explanation:
Process
1.- Find two points of the line
A ( 0, 1)
B ( 1, -3)
2.- Find the slope of the line



m = -4
3.- Find the equation of the line
y - y1 = m (x - x1)
y - 1 = -4( x - 0)
y -1 = -4x
y = -4x + 1
Answer:
it's A i just took the test
Answer:i dont know but plz give brainly
Step-by-step explanation:
Answer:
28
Step-by-step explanation: