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umka21 [38]
3 years ago
7

Jake’s map shows the distance from the Bake Stars Cafe to the restaurant supply store as 3 centimeters. If the scale of the map

is 1 centimeter to 8 kilometers, what is the real distance from the shop to the store?
Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

The real distance from shop to store is 24 kilometers.

Step-by-step explanation:

Given:

Distance from the Bake Stars Cafe to the restaurant supply store on map = 3 cm

Also Given:

Scale of the map 1 cm = 8 km

We need to find the real distance from the shop to the store.

Solution:

Now we know that;

Distance from shop to store on map =3 cm

1 cm = 8 km

3 cm = Real distance from shop to store

By using Unitary method we get;

Real distance from shop to store = 8\times3 =24 \ km

Hence The real distance from shop to store is 24 kilometers.

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Find the perimeter of the trapezoidal brick to the nearest tenth of an inch.
Artemon [7]

Answer:

<h2>The perimeter of the figure is 50 feet.</h2>

Step-by-step explanation:

The trapezoid is attached.

Remember, the perimeter is the sum of all sides. But, in this case, we don't know the lenght of all sides. So, we need to find them.

Notice that the missing side on the left is congruent to the vertical leg of the right triangle. So, we use the Pythagorean Theorem to find it. Also, observe that the horizontal leg of the right triangle is 6 feet long.

10^{2} =6^{2} +h^{2} \\h^{2}=100-36\\ h=\sqrt{64}=8

Now, we can sum all sides to find the perimeter

P=8 +13+10+19=50 \ ft

Therefore, the perimeter of the figure is 50 feet.

4 0
4 years ago
What is the distance from the origin to point A graphed on the complex plane below
Valentin [98]

Answer:

B) \sqrt{13}

Step-by-step explanation:

1.  d = \sqrt{(-3-0)^2+(-2-0)^2}

2. d=\sqrt{(-3)^2+(-2)^2}

3. d=\sqrt{9+4}

4. d=\sqrt{13}

\sqrt{13} = 3.60555..

7 0
3 years ago
Billy has 150 Star Wars action figures. The figures made in 1977 sold for $20 each
Brums [2.3K]
Your two equations would be:
150 = x + y
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after solving,
95 for $20
55 for $12
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3 years ago
Estimate 420983+39932
zavuch27 [327]

460915 is the answer


4 0
3 years ago
What is the solution set of the quadratic inequality f(x) greater than or equal to 0
stellarik [79]

ANSWER

{x | x \in \: R}

EXPLANATION

From the graph, the given quadratic inequality is

{(x + 3)}^{2}  \geqslant 0

We can see that the corresponding quadratic function is a perfect square.

Since the graph opens upwards and it is always above the x-axis, any real number you plug into the inequality, the result is greater than or equal to zero.

Hence the solution set is

{x | x \in \: R}

The correct answer is A

3 0
3 years ago
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