Volume of solution in liters:
5.00 x 10² mL / 1000 => 0.5 L
number of moles:
mass of solute / molar mass
21.1 / 119.0 => 0.1773 moles
Molarity = number of moles / volume
M = 0.1773 / 0.5
M = 0.355 mol/L
Answer C
<span>hope this helps!</span>
Answer:If the diagram shows 3 m and 6 m the answer would be 2.
Explanation:
When you take 7.83 g of H2, you convert to moles by dividing by the molar mass (2.02) and multiply by the number of H2s over H2Os. Then do the same for the O2. the limiting reagent in this case is the Oxygen by what I calculated.
Remark
The question with these kind of problems is "Which R do you use?" That's where dimensional analysis is so handy. You must look at the units of the givens and choose your R accordingly. You'll see how that works in a moment.
You need to list the givens along with their units and in this case the property you want to solve for. You need all that to determine the R value
Givens
n = 0.25 moles
T = 35°C = 35 + 273.15 = 308.15°K
V = 6.23 L
Pressure = P in kPa
Which R
The units of the R you want has to have units of moles, kPa, °K and liters
The R that you want is 8.314
<em><u>Formula</u></em>
PV = nRT
P 6.23 = 0.25 * 8.314 * 308.15 Combine the left
P*6.23 = 640.5
P = 640.5/6.23 = 102.81 The answer should be 100 kpA of 1.0 * 10^2 kPa
because the number of moles has only 2 sig digs.
But if sig digs are not a problem 102.8 is likely close enough.
Second Question
You are going to have to clean up the numbers. I think I've got only 1 chance at this. The partial pressures of the 2 gases will add up to the total pressure. So the total pressure was 100 approx and the water vapor was 3.36 kPa. The difference is
Total = air + water vapor
100.18 = air + 3.36 about Subtract 3.36 from both sides.
100.18 - 3.36 = 96.82 about. Pick the answer that is closest to that. I'll clean up the numbers if I can.
Answer C
