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3 years ago

True or false?

Chemistry

2 answers:

Elina [12.6K]3 years ago

6 0

Answer:

Its true I think but I may be wrong lol

kondaur [170]3 years ago

4 0

Answer:

An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged An apple, potato, and onion all taste the same if you eat them with your nose plugged

Explanation:

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If the relative rate of diffusion of ozone as compared to chlorine is 6:3 and further if the density of chlorine is 36 Find out

Alexandra [31]

Answer:

The density of ozone is 4.24.

Explanation:

The relation between the relative rate of diffusion and density is given by :

$r\propto \dfrac{1}{\sqrt d}$

The given ratio of the relative rate of diffusion of ozone as compared to chlorine is 6:3.

Let the density of ozone is d₂.

$\dfrac{r_1}{r_2}=\sqrt{\dfrac{d_2}{d_1}} \\\\\dfrac{6}{3}=\sqrt{\dfrac{d_2}{36}} \\\\3=\dfrac{\sqrt{d_2}}{6}\\\\d_2=\sqrt{18} \\\\d_2=4.24$

So, the density of ozone is 4.24.

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3 years ago

Use bond energies from Table 10.3 in the textbook to estimate the enthalpy change (ΔH) for the following reaction. C2H2(g)+H2(g)

Digiron [165]

Answer: $=176.6kJmol^{-1}$

Explanation:Bond energy of H-H is 436.4 kJ/mole

Bond energy of C-H is 414 kJ/mol

Bond energy of C=C is 620 kJ/mol

Bond energy of C≡C is 835 kJ/mol

$\Delta H= {\text {sum of bond energies of reactants}}- {\text {sum of bond energies of products}}$

$\Delta H$ = {1B.E(C≡C)+2B.E(C-H) +1B.E(H-H)} - {1B.E(C=C)+4B.E(C-H)}

$\Delta H= {1B.E(835kJmole^{-1})+2B.E(414kJmole^{-1}) +1B.E(436.4kJmole^{-1})} - {1B.E(620kJmole^{-1})+4B.E(414kjmole^{-1})}$

$=176.6kJmol^{-1}$

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4 years ago

The air you breathe is made of 21% oxygen and 78% nitrogen. The oxygen in air is the _____ and the nitrogen is the _____.

Flura [38]

Here are the answers that would best complete the given statement above. The air you breathe is made of 21% oxygen and 78% nitrogen. The oxygen in air is the SOLUTE and the nitrogen is the SOLVENT. In a given mixture, the reagent having the highest percentage of amount is always the solvent and the one or ones having the lower percentages are the solutes. Hope this answer helps.

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3 years ago

A compound is composed of 13% carbon, 4.3% hydrogen, 30.4% nitrogen, and 52.2% oxygen. The mystery compound has a molar mass of

vredina [299]

Answer:

C₂H₈N₄O₆ is the molecular formula for the compound

Explanation:

Data from the problem:

13 g of C in 100 g of compound

4.3 g of H in 100 g of compound

30.4 g of N in 100 g of compound

52.2 g of O in 100 g of compound

Firstly we determine, the mass of each in 184 g of compound, which is 1 mol

(13 g / 100 g) . 184 g = 24 g C

(4.3 g / 100 g) . 184 g = 7.91 g H ≅ 8 g H

(30.4 g / 100 g) . 184 g = 56 g N

(52.2 g / 100 g) . 184 g = 96 g O

And now, we divide the mass by the molar mass of each to determine the moles:

24 g C / 12 g/mol = 2 mol C

8g H / 1 g/mol = 8 mol H

56 g N / 14 g/mol = 4 mol N

96 g O / 16 g/mol = 6 mol O

So the molecular formula of the compound is C₂H₈N₄O₆

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3 years ago

In common speech, some people may use the terms hypothesis and theory interchangeably. In science, however, the terms have diffe

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Answer:

A hypothesis is something you can test a theory is just a thought that you have.

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3 years ago

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