I'd split the shape into 1 rectangle, and two semicircles. To find the area of the rectangle, you would do 4 + 4 + 4 = 12, and then 6 × 12 = 72
![m^{2}](https://tex.z-dn.net/?f=%20m%5E%7B2%7D%20)
To do the semicircles, the area of a circle is
![\pi r^{2}](https://tex.z-dn.net/?f=%20%5Cpi%20r%5E%7B2%7D%20)
so, using 3.14 as pi, you would do 3.14 ×
![2^{2}](https://tex.z-dn.net/?f=%202%5E%7B2%7D%20)
= 3.14 × 4 = 12.56. Because there are two semicircles, you can just leave this. Now, you add it on to 72 to get 84.56
![m^{2}](https://tex.z-dn.net/?f=%20m%5E%7B2%7D%20)
I hope this helps!