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mrs_skeptik [129]
3 years ago
10

The radius of a circle is 1 centimeter. What is the circle's circumference?

Mathematics
1 answer:
igomit [66]3 years ago
6 0

Answer:

6.28 cm

Step-by-step explanation:

The formula for the circumference of a circle with radius r is C = 2*pi*r.

If we let pi = 3.14 and r = 1 cm, then the circumference of this circle is

C = 2(3.14)(1 cm) = 6.28 cm

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Write two equivalent expressions to represent the area of the rectangle below.
Goshia [24]

Answer:

A=(n-3)2\ units^2

A=(2n-6)\ units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

A=LW

where

L is the length of rectangle

W is the width of rectangle

In this problem we have

L=(n-3)\ units\\W=2\ units

substitute

A=(n-3)2\ units^2

Apply distributive property

A=2(n)-2(3)

A=(2n-6)\ units^2

4 0
3 years ago
Use the figure and flowchart Proof to answer the question which property of equality accurately completes reason C
blagie [28]

Answer:

Step-by-step explanation:

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7 0
4 years ago
Read 2 more answers
4/3 divided 7/8 help
Leni [432]

Answer:

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5 0
3 years ago
J.k. Rowling and R.L. Stone are both ready hunger games . J.k. Reads 35 pages every 2 hours and R.L. Reads 45 pages every 3 hour
san4es73 [151]

Answer:

The rate of change for each reader is :

For J K Rowling :  17 and a half pages per hour

For R L Stone :  15   pages  per hour

Step-by-step explanation:

Here the reading rate of each reader is given as:

J.K. Reads 35 pages every 2 hours.

So, the number of pages read by J K  in 2 hours  = 35 pages

⇒ The number of pages read per hour  =  35 / 2  = 17 . 5 pages

So, the pages read by J K Rowling in 1 hour is 17 and a half pages.

R L Stone reads 45 pages every 3 hours.

So, the number of pages read by R L  in 3 hours  = 45 pages

⇒ The number of pages read per hour  =  45 / 3  = 15 pages

So, the pages read by R L Stone in 1 hour is 15 pages.

Hence, the rate of change for each reader is :

For J K Rowling :  17 and a half pages  per hour

For R L Stone :  15   pages  per hour

5 0
4 years ago
Suppose that the relation G is defined as follows.
Serga [27]

G:{3,4,6}->{0,9}

The pairs represent the input (first number in each pair) and the result (second nu.ber in each pair) for the relation G. for example G(3)=9.

The domain is the set of values that the relation can act upon. The range is the set of the values the results can take

6 0
3 years ago
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