What is the volume of a cone with the height of 5.5 and a radius of 4
2 answers:
Answer:
29.33π cm³ or 92.10 cm³
Step-by-step explanation:
To find the volume of a cone with height 5.5 and radius 4, we will simply use the formula;
volume of a cone = π r² h
h = 5.5 and r= 4, we will simply plug in these values into our formula
volume of a cone = × π × (4)² (5.5)
= ×π × 16 × 5.5
=88π / 3
=29.33π
volume of cone = 29.33π
But π= 3.14
plugging in π=3.14, we have;
volume of cone = 29.33(3.14)=29.10
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The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is .
Given
The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable.
<h3>The magnitude of an earthquake</h3>The magnitude of an earthquake is a measure of the energy it releases.
For an earthquake with 1,000 times more intense than a standard earthquake.
The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is;
Hence, the equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is .
To know more about the magnitude of earthquakes click the link given below.
Answer:
15°
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
