Answer:
P(C4) = 0.0711
Step-by-step explanation:
consider the first draw = 15/23 since it cannot be a blue ball
The second draw = 21/29 since 6 more red balls will be added after the draw since a blue ball cannot be drawn
the third draw = 27/35 since 6 more red balls will be added after each draw since a blue ball cannot be drawn
therefore the total number of red balls will be = 15 + 6 + 6 + 6 = 33 red balls after the 4th draw. the total ball now in the urn= 33 red + 4 blue = 41
Hence the probability of drawing a blue ball at the fourth draw after drawing red balls at the previous attempts = 8/41
P(C4) = P ( fourth ball is blue ) * P( first ball red)*P(second ball red) *P(third ball red )
= (8/41) * (15/23) * (21/29)* (27/35) = 0.0711
Answer:
the difference is that the 2 extra LARGE containers weigh bigger than the
6 small ones
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let's solve one of them for x.
Add 4
Divide by 3.
Now, plug the value of y in the formula, or you can plug the value of x in the other equation. I'll take this one.
Multiply by 3 to get rid of the denominator.
add x
Combine like terms;
Divide by 4.
Simplify.
Now that you found the value of x, replace it in any of the equations to find y.
Proof:
Answer:
Step-by-step explanation:
The answer is 11.66 or 11.67 depending on how you round the decimal
