8^2, 4^3, and 2^6 are 3 ways
It is easier to understand the problem if you create a number based on the criteria and then perform the computations. I am going to choose: 111 22 33 4
There are 10 options for the first "1" and only 1 option for the other two 1's
There are 9 remaining options for the first "2" and only 1 option for the other 2
There are 8 remaining options for the first "3" and only 1 option for the other 3
There are 7 remaining options for the "4"
10 x 1 x 1 x 9 x 1 x 8 x 1 x 7
10 x 9 x 8 x 7 = 5,040
Answer: 5,040
Answer:
Option C) 4 congruent sides
Step-by-step explanation:
From the construction done as per statements given in the question.
AB is a common radius of circles A and circle B.
Since AB = AC = AD ( radii of circle A)
And AB = BC = BD (radii of circle B)
Therefore, AB = AC = AD = BD = BC
All sides of quadrilateral ABCD are equal.
Option C is the answer.
Answer:
b = -1/10.
Step-by-step explanation:
(2i/2+i)-(3i/3+i)
= 2i(3 + i) - 3i(2 + i) / (2 + i)(3 + i)
= 6i + 2i^2 - 6i - 3i^2 / (2 + i)(3 + i)
= (-2 + 3) / (6 + 5i - 1)
= 1 / (5 + 5i)
Now we multiply top and bottom by 5 - 5i :
= 5 - 5i / (5 + 5i)(5 - 5i)
= 5 - 5i / 25 -25i^2
= 5 - 5i / 50
= 1/10 - 1/10i
