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nikdorinn [45]
3 years ago
8

A coaster is designed to hold 2 different drinks. Find the are of the coaster. Round your answer to the nearest hundredth.

Mathematics
2 answers:
netineya [11]3 years ago
8 0

Answer:

You will save points if you try to solve it urself first Lol

22.065

Explanation: 5x3=15

A=1.5x1.5x3.14

2.25x3.14

7.065

15

——————-

22.065in2

Nonamiya [84]3 years ago
6 0
Answer 22 in rounded or 22.065 in
Area of a rectangle is 5 x 3 = 15 in
Area of the circles is 3.14 x 1.5 x 2 =7.065
Finally 7.065 + 15 = 22.065 squared in
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8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
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Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

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