The the run on the other section if its rise is 4.3 m = 9.03m
<h3>How top solve for the run</h3>
To get the run on the other section we have to use the cross multiplication formula, using m1 = m2
Such that we would have
3.0/6.3 = 4.3/x
6.3 * 4.3 = 3.0 * x
= 27.09 = 3x
divide through by 3
x = 9.03
Hence we conclude that the the run on the other section if its rise is 4.3 m = 9.03m
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Answer:
Step-by-step explanation:
a² - b² = (a+ b)(a - b)
1) (2n-4/2n) ÷ (n^2-4/n)

2) [y^2-36/y^2-49] ÷[ y+6/y-7]

3) [m^2-1/ m^2-m] ÷ [m^2-7m-8/3m
]

Hint : m² - 7m - 8
sum = -7
Product = -8
Factor = (-8), 1
m² - 7m - 8 =m² - 8m + m - 8
= m*(m - 8) + (m-8)
= (m - 8)(m +1)
Answer:
Probability of having two hits in the same region = 0.178
mu: average number of hits per region
x: number of hits
e: mathematical constant approximately equal to 2.71828.
Step-by-step explanation:
We can describe the probability of k events with the Poisson distribution, expressed as:

Being μ the expected rate of events.
If 535 bombs hit 553 regions, the expected rate of bombs per region (the events for this question) is:

For a region to being hit by two bombs, it has a probability of:

Fractions are just division. 2 ÷ 2 = 1, so 2/2 = 1. Because 1/2 can't be simplified to a whole number, the answer is 1 1/2.