if you have a geometric series in sigma notation , how do you find the common ratio without expanding the series ?

Can someone plz help me find the area for this composite figure plzzzz I beg u

Anarel [89]

$S_1 = \frac{a+b}{2}h = \frac{7+9}{2}*5=\frac{18*5}{2}= 9 * 5 = 45~m^2$

$S_\triangle = \frac{ab}{2} = \frac{5*9}{2} = \frac{45}{2} = 22,5~m^2$

$S = S_1 + S_\triangle = 45 + 22,5 = 67,5~m^2$

Answer: 67,5 m².

5 0

3 years ago

Read 2 more answers

a game at carnival has 4 color on a wheel, as seen in the diagram. Each section of the wheel is the same size.<br /> Julie

Temka [501]

So there is 10 spaces with 4 of them blue and 3 yellow 2 red and a green
so their is a 40% of blue 30%yellow 20%of red and10% of green

next question 0-9 well this is a trick there are 10 spaces and has nothing to do with colors just number them 0-9 like this 0123456789

4 0

3 years ago

If Adam buys 5 snakes at 20% off and each snake costs s dollars, which expression is NOT equivalent to the situation stated?

Liula [17]

25, because yes and because 20% is not an accurate number for 5 snakes to have

5 0

3 years ago

f a Chinook salmon is 35.5 inches long, rank the following lengths from most accurate to least accurate. 35 inches 37.2 inches 3

harina [27]

1. 35 (it's .5 inches off)
2. 37.2 (it's 1.7 inches off)
3. 32 (it's 3.5 inches off)
4. 30.984 (it's 4.5 inches off)

8 0

3 years ago

6.3 The daily amount of coffee, in liters, dispensed by a machine located in an airport lobby is a random variable X having a co

dexar [7]

Answer:

a) 60% probability that on a given day the amount of coffee dispensed by this machine will be at most 8.8 liters.

b) 70% probability that on a given day the amount of coffee dispensed by this machine will be more than 7.4 liters but less than 9.5 liters

c) 50% probability that on a given day the amount of coffee dispensed by this machine will be at least 8.5 liters

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

The probability of X being higher than x is:

$P(X > x) = 1 - \frac{x - a}{b-a}$

The probability of X being between c and d is:

$P(c \leq X \leq d) = \frac{d - c}{b - a}$

For this problem, we have that:

$a = 7, b = 10$

(a) at most 8.8 liters;

$P(X \leq 8.8) = \frac{8.8 - 7}{10 - 7} = 0.6$

60% probability that on a given day the amount of coffee dispensed by this machine will be at most 8.8 liters.

(b) more than 7.4 liters but less than 9.5 liters;

$P(7.4 \leq X \leq 9.5) = \frac{9.5 - 7.4}{10 - 7} = 0.7$

70% probability that on a given day the amount of coffee dispensed by this machine will be more than 7.4 liters but less than 9.5 liters

(c) at least 8.5 liters.

$P(X > 8.5) = 1 - \frac{8.5 - 7}{10 - 7} = 0.5$

50% probability that on a given day the amount of coffee dispensed by this machine will be at least 8.5 liters

3 0

3 years ago