if you have a geometric series in sigma notation , how do you find the common ratio without expanding the series ?
1 answer:
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Answer:
The point at which center of the image circle located is (-2, -3) so second option is correct.
Step-by-step explanation:
Given equation of circle is:
(i)
The general equation of circle is mentioned below,
(ii)
Here 'r' represents the radius of the circle and (h,k) shown the center of the circle.
By comparing equation (i) and equation (ii), we get
r^2 = 9
r = 3
So the center of given circle is (h,k) = (3,-4)
Also, the circle is translated 5 units left, that is towards the -x-axis. Therefore h = 3 - 5 = -2
Also, the circle is translated 1 unit up, that is towards the +y-axis. Therefore k = -4 + 1 = -3
Hence, the point at which center of the image circle located is (-2, -3) so second option is correct.