3. Find the missing value. a. The mean is 8: b. 5, 11, 9, 7, 6, X

mario62 [17]

Answer:

72

Step-by-step explanation:

68 69 71 71 71 73 74 75 75 78 and then cross off each number until you reach the middle. You will see 71 and 73 next to each other, what's in-between those two numbers? 72!

7 0

2 years ago

Lee is thinking of 2 numbers, the product is 18.the quotient is 2. what are yhe two numbers?

jeka94

$xy=18\\
\dfrac{x}{y}=2\\\\
xy=18\\
x=2y\\\\
2y\cdot y=18\\
2y^2=18\\
y^2=9\\
y=-3 \vee y=3\\\\
x=2\cdot (-3) \vee x=2\cdot 3\\
x=-6 \vee x=6\\\\
\boxed{(x,y)=\{(-6,-3),(6,3)\}}$

4 0

3 years ago

Hey guys I have a hard time with these questions. Can someone explain it to me? :)

frutty [35]

The slope would be 0

This is basically how you do it if you need more help let me know

6 0

2 years ago

Read 2 more answers

What is the equation of the line with a slope of 3/4 that goes through the point (4, 1) in slope-intercept form?

Svetach [21]

Answer:

$y=\frac{3}{4}x+-2$

Step-by-step explanation:

We do not have enough information for slope intercept form. But we can use the point-slope formula to find the information. The formula is $y -y_{1} =m(x -x_{1})$ where we substitute a point (x,y) for $(x_{1},y_{1})$ .

We have m=3/4 and (4, 1). We input m and $x_{1} =4\\y_{1}=1$ .

$y-1=\frac{3}{4} (x-4)$

We now simplify the parenthesis and solve for y.

$y-1=\frac{3}{4} (x-4)\\y-1=\frac{3}{4}x+\frac{3}{4} (-4)$

We convert -4 into a fraction with 1 as the denominator.

$y-1=\frac{3}{4}x+\frac{3}{4} (\frac{-4}{1} )\\y-1=\frac{3}{4}x+\frac{-12}{4}\\y-1=\frac{3}{4}x+-3$

We add 1 to both sides to isolate y,

$y-1+1=\frac{3}{4}x+-3+1\\y=\frac{3}{4}x+-2$

This is slope intercept form. The line as slope 3/4 and y-intercept (0,2) or b=2.

4 0

3 years ago

Find the value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2

soldier1979 [14.2K]

The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

Solution:

Given that line is passing through point (-5, 2) and (3, r)

Slope of the line is $\frac{-1}{2}$

Need to determine value of r.

Slope of a line passing through point $\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)$ is given by following formula:

$\text { Slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ --- eqn 1

$\text { In our case } x_{1}=-5, y_{1}=2, x_{2}=3, y_{2}=\mathrm{r} \text { and } m=-\frac{1}{2}$

On substituting the given value in (1) we get

$\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}$

Hence the value of "r" is -2

8 0

3 years ago