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2 years ago

I NEED HELP ASAP. PLEASE HELP MEE!

Mathematics

1 answer:

olga2289 [7]2 years ago

6 0

Answer:

9,6

Step-by-step explanation:

Hopefully this helps you :)

pls mark brainlest ;)

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PLEASE HELP !!!

kobusy [5.1K]

Help with what. Hahahaha

7 0

2 years ago

Seventh grade

victus00 [196]

Answer:

Maybe it could be six or 30

Step-by-step explanation:

7 0

2 years ago

Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ

const2013 [10]

Answer:

$\frac{(2a + 1)^2}{50a}$

Step-by-step explanation:

Given

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$

Required

Find the equivalent

We start by changing the / to *

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$

$\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}$

Factorize 10a - 5

$\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}$

Expand 4a² - 1

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}$

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}$

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: $a^2- b^2= (a+b)(a-b)$

The expression becomes

$\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}$

Combine both fractions to form a single fraction

$\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}$

Divide the numerator and denominator by 2a - 1

$\frac{(2a + 1)((2a + 1)}{5*10a}$

Simplify the numerator

$\frac{(2a + 1)^2}{5*10a}$

$\frac{(2a + 1)^2}{50a}$

Hence,

$\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}$ = $\frac{(2a + 1)^2}{50a}$

4 0

2 years ago

What is the probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator

kirill [66]

Answer:

See explanation

Step-by-step explanation:

Total number of letters = n! = 10

Permutation for 10 letters = n!

= 10!

= 10*9*8*7*6*5*4*3*2*1

= 3628800

From n letters:

Number of A = 2

Number of C = 2

Number of L = 2

A₁, A₂, C₁, C₂, L₁, L₂, O, R, T, U

Out of 3628800 permutations the word calculator can be spelled as:

C₁ A₁ L₁ C₂ U L₂ A₂ T O R

C₂ A₂ L₂ C₁ U L₁ A₁ T O R

and so on

So total number of different permutations are

(permutation of number of letters) / permutation of (number of As * number of Cs * number of Ls)

= 10! / (2! 2! 2 !)

= 10*9*8*7*6*5*4*3*2*1 / (2*1) (2*1) (2*1)

= 3628800 / 2 * 2 * 2

= 3628800 / 8

= 453600

Hence probability that a randomly selected permutation of the letters A, A, C, C, L, L, O, R, T, U would spell "calculator" is:

1 / total number of different permutations

= 1 / 10! / (2! 2! 2 !)

= 1/453600

= 0.000002

8 0

2 years ago

Please help with this

dimulka [17.4K]

Answer:

A is the answer I think. Either way, they are congruent

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers