Answer:
<u>David gets £24, Stephen gets £36, and June gets £36.</u>
Step-by-step explanation:
Firstly, add the ratio values together.
2:3:3 ⇒ 2 + 3 + 3 = 8
Next, divide £96 (your total) by 8.
£96 ÷ 8 = £12
Now, we have the number of pounds for 1 value.
Multiply 12 by each ratio value.
<u>12 × </u><u>2</u> : <u>12 × </u><u>3</u> : <u>12 × </u><u>3</u>
= 24:36:36
Therefore, David gets £24, Stephen gets £36, and June gets £36.
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Answer: Approximately 52.87 cm.
Step-by-step explanation:
Circumference is diameter times pie to divide the circumference by pie.
166/3.14 use 3.14 as an approximation for pie.
166/3.14 = 52.87 rounded to the nearest hundredth
Step-by-step explanation:
i = interest 3% for 30 years
This is a simple dynamical system for whom the the solutions are given as
](https://tex.z-dn.net/?f=S%3DR%5B%5Cfrac%7B%28i%2B1%29%5En-1%7D%7Bi%7D%5D%28i%2B1%29)
putting values we get
S=2000[\frac{(1.03)^{30}-1}{0.03}](1.03)
= $98005.35
withdrawal of money takes place from one year after last payment
To determine the result we use the present value formula of an annuity date

we need to calculate R so putting the values and solving for R we get
R= $6542.2356
Answer:
a. The critcal points are at

b. Then,
is a maximum and
is a minimum
c. The absolute minimum is at
and the absolute maximum is at 
Step-by-step explanation:
(a)
Remember that you need to find the points where

Therefore you have to solve this equation.

From that equation you can factor out
and you would get

And from that you would have
, so
.
And you would also have
.
You can factor that equation as 
Therefore
.
So the critcal points are at

b.
Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

Then,
is a maximum and
is a minimum
c.
The absolute minimum is at
and the absolute maximum is at 
Answer:
BC = 8 and EF = 8.
Step-by-step explanation:
Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).
Set BC and EF equal to each other.
x + 6 = 3x + 2
Subtract x from both sides.
6 = 2x + 2
Subtract 2 from both sides.
4 = 2x.
Divide 2 on both sides.
x = 2.
Substitute 2 for x.
BC = 2 + 6
BC = 8
Since we already know that EF is congruent to BC, EF is also 8.
EC = 3(2) + 2
EC = 6 + 2
EC = 8