There's a quick, easy, sloppy way, and there's a good math way.
Here's the good math way:
If the integers are consecutive, then you can call them 'x', (x+1), and (x+2).
We know what their sum is, so let's add them up:
x + (x+1) + (x+2) = 336
x + x+1 + x+2 = 336
Combine the terms that are alike on the left side:
3x + 3 = 336
Subtract 3 from each side: 3x = 333
Divide each side by 3 : <u> x = 111</u>
The integers are<em> 111, 112, </em>and<em> 113</em> .
Alright so if you divided 658 by two you get 329 (which would be the maximum amount of adults with students). Multiply $8.50 by 329 and do the same with $4.50. Add the two totals together to get the amount of money Lara would make.
You +8 on each side then solve you should get n=6
Answer:
i think B or D
Step-by-step explanation:
The equation is already in slope - intercept form y=mx+b, where m = slope, so m=4
The slope is 4