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Alik [6]
3 years ago
6

48 is what percent of 60?

Mathematics
1 answer:
Mariulka [41]3 years ago
5 0
48 is 80% of 60

Divide 48 over 60:
\frac{48}{60} = 0.8

Convert your decimal to a percentage:
0.8 \times 100 = 80
You might be interested in
Use the Distributive Property to simplify the expression: 2(4a+6b)
Anarel [89]
8a+12b because you multiply 2 by each number. For example 4a times 2 is 8a and 6b times 2 is 12b

Hope that helped :)
4 0
3 years ago
Which lists the steps in the correct order to find the median of this data set?
Fofino [41]

The median of the data set can be found as follows:

1. Put the numbers in order (from least to the greatest): 16, 18, 23, 24, 29, 30

2. Cross off high/low pairs: 16, 18, (23, 24,) 29, 30

3. Divide the sum by 2: (23 + 24)/2 = 23.5

<h3>What is the Median?</h3>

The median of a data set is the data value at the middle of the data set when it is ordered.

Steps to find the median of the data set, 24, 16, 23, 30, 18, 29:

1. Put the numbers in order (from least to the greatest)

16, 18, 23, 24, 29, 30

2. Cross off high/low pairs: 16, 18, (23, 24,) 29, 30

3. Divide the sum by 2: (23 + 24)/2 = 23.5

4

The median is therefore, 23.5.

Learn more about the median on:

brainly.com/question/26177250

3 0
2 years ago
A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
Find the area of the composite figure to the nearest hundredth.
Lyrx [107]

Answer:

745.31

Step-by-step explanation:

1.  12.5^2 * 2 = 312.5

2. (3,14 * 156,25)/2 = 245.31

3.  (30 * 12.5)/2 = 187.5

4. 187.5 + 245.31 + 312.5 = 745.31

4 0
3 years ago
What is 13^2*10<br><br> A.1690<br> B.1700<br> C.1800<br> D.169000
shutvik [7]

A. 1690.


You can get this answer by doing 13 to the power of 2 and then multiplying that answer by 10.

5 0
3 years ago
Read 2 more answers
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