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Paladinen [302]
3 years ago
6

Which expression has a negative value? A) B)−1×2×−3×4×−5 C)1×−2×−3×−4×−5 D)1×−2×3×−4×5

Mathematics
1 answer:
MArishka [77]3 years ago
6 0

Answer:

B

Step-by-step explanation:

B) -1*2*-3*4*-5=-2*-3*4*-5=6*4*-5=24*-5=-120

C) 1*-2*-3*-4*-5=-2*-3*-4*-5=6*-4*-5=-24*-5=120

D) 1*-2*3*-4*5=-2*3*-4*5=-6*-4*5=24*5=120

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4 years ago
A bowl contains 25 balls numbered 1 to 25. A ball is drawn and its number is noted. Without replacing the first ball, another ba
puteri [66]

The probability that the numbers on both balls are odd numbers is \frac{13}{50}

<em><u>Solution:</u></em>

<em><u>The probability of an event is given as:</u></em>

probability =\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}

Given that, bowl contains 25 balls numbered 1 to 25

The sample space is given as;

{ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25 }

Therefore,

Total number of possible outcomes = 25

A ball is drawn and its number is noted. Without replacing the first ball, another ball is drawn.

Numbers on both balls are odd numbers

<em><u>Let us first find the probability that first ball is odd</u></em>

Favorable outcome = odd numbers

Favorable outcome = 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25

Number of favorable outcomes = 13

Thus, probability is given as:

probability = \frac{13}{25}

Now Without replacing the first ball, another ball is drawn.

<em><u>Find the probability that second ball is odd number</u></em>

Without replacing means that ball is not put back into bowl

So, sample space = 25 - 1 = 24

Total number of possible outcomes = 25

Number of favorable outcomes = 13 - 1 = 12

Thus, probability is given as:

probability = \frac{12}{24}

<em><u>Probability that the numbers on both balls are odd numbers is:</u></em>

Multiply both the probabilities

\text{ probability of odd } = \frac{13}{25} \times \frac{12}{24} = \frac{13}{50}

Thus, probability that the numbers on both balls are odd numbers is \frac{13}{50}

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