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3 years ago

Choose a method the find the product 16x60

2 answers:

5 0

The product is 960 because 0x6=0,6×6=36 so 60 times 6 is 360 thenn you go to the bottom & bring down one zero under your first zero ,multiply 1 times the zero which equals 0 ofc & 6×1=6 so it'll be 360 + 600= 960

madam [21]3 years ago

5 0

The answer is 960 because 16 times 60 is =960

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(x^2+5)(8x-3) multiply

klio [65]

X^2 x 8x -3x^2 +5 x 8x -5 x 3

8x^3 -3x^2 +40x -15

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3 years ago

Did I do everything right on the binder paper?

gregori [183]

Your first answer is wrong for the Garden
9 is the length from the walkway to the garden, your equation should be :

A=6(3)
A=18

this means you'd have to add all the numbers again :
18 + 40 + 24=82

all your other answers are correct

hope this helped

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3 years ago

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Find the value of x.

Elanso [62]

Answer:

A. 7

Step-by-step explanation:

The problem is poorly specified, so <em>technically cannot be answered with a specific number</em>.

If we assume the "horizontal" lines are all parallel, then the one marked 21-x has a length that is the average of the other two:

(17 +11)/2 = 21 -x

14 = 21 -x

x = 21 -14 = 7

The value of x is 7.

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The attachment shows what happens when the lines are not parallel. The range of the midline lengths is from 3 to 14 for the segment lengths shown.

4 0

3 years ago

What is the pH of a buffer that is 0.6 M HF and 0.2 M NaF? The Ka of HF is 6.8 Ã 10â4. What is the pH of a buffer that is:______

ollegr [7]

Answer:

The correct option is d

Step-by-step explanation:

From the question we are told that

The concentration of HF is [HF] = 0.6 M

The concentration of NaF is $[NaF ] = 0.2 M$

The Ka of HF is $K_a = 6.8 *10^{-4} \$

Generally HF(Hydrogen fluoride ) is ionized as follows

$HF_{(aq)} + H_2 O _{(l)} \rightleftharpoons H_3O^+ _{(aq) } + F^- _{(aq)}$

Generally NaF(Sodium fluoride ) is ionized as follows

$NaF_{(aq)} + H_2 O _{(l)} \rightleftharpoons Na^+ _{(aq) } + F^- _{(aq)}$

Generally the from Henderson-Hasselbalch equation the pH of the buffer is mathematically represented as

$pH = pKa + log [\frac{[NaF ]}{HF} ]$

=> $pH = -log(K_a) + log [\frac{[NaF ]}{HF} ]$

=> $pH = -log(6.8 *10^{-4}) + log [\frac{[0.2 ]}{0.6} ]$

=> $pH = 2.69$

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3 years ago

Triangle ABC was dilated and translated to form similar triangle A'B'C'.

Gelneren [198K]

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dilation factor = A'/A = B'/B = C'/C

8 0

4 years ago

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