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Angelina_Jolie [31]
3 years ago
15

HELP!!! WHICH FUNCTION HAS THE LARGEST Y INTERCEPT

Mathematics
2 answers:
madam [21]3 years ago
8 0

The function that has the largest y-intercept is the function that has the largest y-value when x = 0.


f(0) = 2(0)^2+3(0)-4 = -4 is the y-intercept of f(x).


When g(0), the value of y is 0


To find the y-intercept of h(x), we find the point where x=0, and see that it equals -2.


Therefore, the function with the largest y-intercept is g(x)

ratelena [41]3 years ago
3 0

For f(x), the function uses the following formula:


ax^2 + bx + c


The y-intercept in this formula is represented by c.

f(x) has a c value of -4, so the y-intercept of f(x) is -4.


For g(x), the y-intercept is found when the graph cross the y-axis.

g(x) cross the y-axis at y = 0, so the y-intercept of g(x) is 0.


For h(x), the y-intercept is found by taking the output at x = 0.

At x = 0, the y value that is output is -2, so the y-intercept is -2.


Compare the three y-intercepts:


f(0) = -4

g(0) = 0

h(0) = -2


-4 < -2 < 0


The function with the greatest y-intercept is g(x), with a y-intercept of 0.

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Step-by-step explanation:

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What is 12/42 when you simplify it 
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Paha777 [63]

Answer:The answers can be calculated by the following steps;

Step-by-step explanation:

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Problem 2: For a recent year, the mean fare to fly from Charlotte, North Carolina to Chicago Illinois, on a discount ticket was
Maru [420]

Answer:

Step-by-step explanation:

n = 12

The mean of the set of data given is

Mean, x = (286 + 290 + 285 + 291 + 287 + 275 + 262 + 289 + 274 + 276 + 297 + 262)/12 = 281.2

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (286 - 281.2)^2 + (290 - 281.2)^2 + (285 - 281.2)^2 + (291 - 281.2)^2 + (287 - 281.2)^2 + (275 - 281.2)^2 + (262 - 281.2)^2 + (289 - 281.2)^2 + (274 - 281.2)^2 + (276 - 281.2)^2 + (297 - 281.2)^2 + (262 - 281.2)^2 = 1409.68

Standard deviation, s = √(1409.68/12) = 10.8

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

1) For the null hypothesis,

H0: µ = 290

For the alternative hypothesis,

H1: µ < 290

This is a left tailed test.

2) Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 12,

Degrees of freedom, df = n - 1 = 12 - 1 = 11

t = (x - µ)/(s/√n)

Where

x = sample mean = 281.2

µ = population mean = 290

s = samples standard deviation = 10.8

t = (281.2 - 290)/(10.8/√12) = - 2.82

Test statistic = - 2.82

3) The decision rule is to reject the null hypothesis if the significance level is greater than the p value.

4) We would determine the p value using the t test calculator. It becomes

p value = 0.0083

5) Since alpha, 0.01 > than the p value, 0.0083, then we would reject the null hypothesis. Therefore, At a 1% level of significance, the sample data showed significant evidence that the mean fare has decreased.

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