Answer: it should be three
Step-by-step explanation:
Answer:
Approximately 54°
Step-by-step explanation:
So we know Angle A, the side opposite to Angle A, and the side opposite to Angle B (the angle we want to find). Given these circumstances, we can use the Law of Sines.
The Law of Sines states that:
![\frac{\sin(A)}{a} =\frac{\sin(B)}{b} =\frac{\sin(C)}{c}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%28A%29%7D%7Ba%7D%20%3D%5Cfrac%7B%5Csin%28B%29%7D%7Bb%7D%20%3D%5Cfrac%7B%5Csin%28C%29%7D%7Bc%7D)
The variables do not really matter. Instead, it's more important that the angle corresponding to the side lines up with each other.
Anyways, since we know Side A, Angle A, and Side B, let's use the first and second ratios:
![\frac{\sin(A)}{a} =\frac{\sin(B)}{b}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%28A%29%7D%7Ba%7D%20%3D%5Cfrac%7B%5Csin%28B%29%7D%7Bb%7D)
Plug in 80° for A, 11 for a, and 9 for b:
![\frac{\sin(80)}{11} =\frac{\sin(B)}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csin%2880%29%7D%7B11%7D%20%3D%5Cfrac%7B%5Csin%28B%29%7D%7B9%7D)
Cross multiply to solve for B:
![9\sin(80)=11\sin(B)](https://tex.z-dn.net/?f=9%5Csin%2880%29%3D11%5Csin%28B%29)
Divide both sides by 11:
![\sin(B)=\frac{9\sin(80)}{11}](https://tex.z-dn.net/?f=%5Csin%28B%29%3D%5Cfrac%7B9%5Csin%2880%29%7D%7B11%7D)
Use the inverse sine function. And finally, use a calculator to solve:
![\angle B =\sin^{-1}(\frac{9\sin(80)}{11} )\\\angle B\approx53.6829\textdegree\approx54\textdegree](https://tex.z-dn.net/?f=%5Cangle%20B%20%3D%5Csin%5E%7B-1%7D%28%5Cfrac%7B9%5Csin%2880%29%7D%7B11%7D%20%29%5C%5C%5Cangle%20B%5Capprox53.6829%5Ctextdegree%5Capprox54%5Ctextdegree)
H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.
<h3>How to Interpret Machine Language?</h3>
A language is referred to as Decidable or Recursive if there is a Turing machine that accepts and halts on every input string w. This tells us that every decidable language is Turing-Acceptable.
Now, we are told that the halting language is reducible to some language B. This means that it is an undecidability via reduction.
Now, Using the idea that “ If A is undecidable and reducible to B, then B is undecidable.” Suppose R decides HALT_TM, we will construct S to decide ATM .
S = “On input (M, B)
This means that H_TM is reduced to HALT_TM and as such, HALT_TM is undecidable.
Read more about machine language at; brainly.com/question/28026656
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<span>891 is divisible by the prime number 3 which results in 297. The same step can be applied 3 more times and the resultant value will be 11. The result 11 cannot be divided any further as it is a prime number. Hence the prime factors of 891 are 3, 3, 3, 3, 11.</span>
Given that total number of principal dancers = 22
We have to find about how many dancers are in the apprentice company.
So let number of dancers in the apprentice company = x
Then half of the dancers in the apprentice company means x/2
Question says that "A ballet company uses all 22 of its principal dancers, plus 1/2 of its apprentice company in a large production" so that means there are 22+x/2 dancers.
Given that there are total 26 dancers so that means we get equation:
22+x/2=26
x/2=26-22
x/2=4
x=4*2
x=8
Hence final answer is that there are total 8 dancers in the apprentice company.