Answer:
The volume of the geometric solid produced is 391 cubic cm ⇒ A
Step-by-step explanation:
<em>When a </em><em>right triangle is rotated about its vertical leg 360°</em><em>, then it formed </em><em>a cone</em><em> its radius is the horizontal leg of the triangle and its height is the vertical lege of the triangle.</em>
The rule of the volume of the cone is V =
π r² h, where
- r is the radius of its base
- h is the length of its height
∵ Triangle XYZ is rotated 360° about the vertical side YZ
∴ It formed a cone with a radius = XZ and a height = YZ
∵ 
∵ YX = 6√3
∴ 
∵ tan(60) = √3
∴
= √3
→ By using cross multiplication
∴ 6√3 = XZ(√3)
→ Divide both sides by √3
∴ 6 = XZ
∵ XZ = r and YZ = h
∴ r = 6 and h = 6√3
→ By using the rule of the cone above
∵ V =
(π) (6)² (6√3)
∴ V ≅ 391 cm³
∴ The volume of the geometric solid produced is 391 cubic cm
(C)
Step-by-step explanation:
Q.E.D means "quod erat demonstrandum" indicating that the proof is completed.
Answer: D
<u>Step-by-step explanation:</u>
In order to increase each ticket by $2, you are ADDING 2 to each value.
So you create a matrix of all 2's and add that to the given matrix.
![\left[\begin{array}{cc}2&2\\2&2\\2&2\end{array}\right] +\left[\begin{array}{cc}8&10\\12&16\\6&8\end{array}\right]\quad =\quad \large \left[\begin{array}{cc}10&12\\14&18\\8&10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%262%5C%5C2%262%5C%5C2%262%5Cend%7Barray%7D%5Cright%5D%20%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D8%2610%5C%5C12%2616%5C%5C6%268%5Cend%7Barray%7D%5Cright%5D%5Cquad%20%3D%5Cquad%20%5Clarge%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D10%2612%5C%5C14%2618%5C%5C8%2610%5Cend%7Barray%7D%5Cright%5D)
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