Answer:
The Linear programming model is given as below
Profit Function: ![P=90X+120Y+150Z](https://tex.z-dn.net/?f=P%3D90X%2B120Y%2B150Z)
Constraints:
![2X+2Y+Z\leq 400](https://tex.z-dn.net/?f=2X%2B2Y%2BZ%5Cleq%20400)
![3X+4Y+6Z\leq 240](https://tex.z-dn.net/?f=3X%2B4Y%2B6Z%5Cleq%20240)
![4X+6Y+5Z\leq 320](https://tex.z-dn.net/?f=4X%2B6Y%2B5Z%5Cleq%20320)
![\dfrac{2X+2Y+Z}{40}\leq 10](https://tex.z-dn.net/?f=%5Cdfrac%7B2X%2B2Y%2BZ%7D%7B40%7D%5Cleq%2010)
![\dfrac{3X+4Y+6Z}{40}\leq 6](https://tex.z-dn.net/?f=%5Cdfrac%7B3X%2B4Y%2B6Z%7D%7B40%7D%5Cleq%206)
![\dfrac{4X+6Y+5Z}{40}\leq 8](https://tex.z-dn.net/?f=%5Cdfrac%7B4X%2B6Y%2B5Z%7D%7B40%7D%5Cleq%208)
![\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19](https://tex.z-dn.net/?f=%5Cdfrac%7B2X%2B2Y%2BZ%7D%7B35%7D%2B%5Cdfrac%7B3X%2B4Y%2B6Z%7D%7B35%7D%2B%5Cdfrac%7B4X%2B6Y%2B5Z%7D%7B35%7D%5Cleq%2019)
Explanation:
As the question is not complete, the complete question is found online and is attached herewith.
Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z
so the maximizing function is the profit function which is given as
![P=90X+120Y+150Z](https://tex.z-dn.net/?f=P%3D90X%2B120Y%2B150Z)
Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours
As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so
![2X+2Y+Z\leq 400](https://tex.z-dn.net/?f=2X%2B2Y%2BZ%5Cleq%20400)
Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours
As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so
![3X+4Y+6Z\leq 240](https://tex.z-dn.net/?f=3X%2B4Y%2B6Z%5Cleq%20240)
Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours
As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so
![4X+6Y+5Z\leq 320](https://tex.z-dn.net/?f=4X%2B6Y%2B5Z%5Cleq%20320)
Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as
![\dfrac{2X+2Y+Z}{40}\leq 10](https://tex.z-dn.net/?f=%5Cdfrac%7B2X%2B2Y%2BZ%7D%7B40%7D%5Cleq%2010)
Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as
![\dfrac{3X+4Y+6Z}{40}\leq 6](https://tex.z-dn.net/?f=%5Cdfrac%7B3X%2B4Y%2B6Z%7D%7B40%7D%5Cleq%206)
Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as
![\dfrac{4X+6Y+5Z}{40}\leq 8](https://tex.z-dn.net/?f=%5Cdfrac%7B4X%2B6Y%2B5Z%7D%7B40%7D%5Cleq%208)
Now the workers are available for 35 hours so the worker available at the machine 1 is given as
![\dfrac{2X+2Y+Z}{35}](https://tex.z-dn.net/?f=%5Cdfrac%7B2X%2B2Y%2BZ%7D%7B35%7D)
That of machine 2 is given as
![\dfrac{3X+4Y+6Z}{35}](https://tex.z-dn.net/?f=%5Cdfrac%7B3X%2B4Y%2B6Z%7D%7B35%7D)
That of machine 3 is given as
![\dfrac{4X+6Y+5Z}{35}](https://tex.z-dn.net/?f=%5Cdfrac%7B4X%2B6Y%2B5Z%7D%7B35%7D)
As the total number of workers is 19 so the constraint is given as
![\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19](https://tex.z-dn.net/?f=%5Cdfrac%7B2X%2B2Y%2BZ%7D%7B35%7D%2B%5Cdfrac%7B3X%2B4Y%2B6Z%7D%7B35%7D%2B%5Cdfrac%7B4X%2B6Y%2B5Z%7D%7B35%7D%5Cleq%2019)
So the Linear programming model is given as below
Profit Function: ![P=90X+120Y+150Z](https://tex.z-dn.net/?f=P%3D90X%2B120Y%2B150Z)
Constraints:
![2X+2Y+Z\leq 400](https://tex.z-dn.net/?f=2X%2B2Y%2BZ%5Cleq%20400)
![3X+4Y+6Z\leq 240](https://tex.z-dn.net/?f=3X%2B4Y%2B6Z%5Cleq%20240)
![4X+6Y+5Z\leq 320](https://tex.z-dn.net/?f=4X%2B6Y%2B5Z%5Cleq%20320)
![\dfrac{2X+2Y+Z}{40}\leq 10](https://tex.z-dn.net/?f=%5Cdfrac%7B2X%2B2Y%2BZ%7D%7B40%7D%5Cleq%2010)
![\dfrac{3X+4Y+6Z}{40}\leq 6](https://tex.z-dn.net/?f=%5Cdfrac%7B3X%2B4Y%2B6Z%7D%7B40%7D%5Cleq%206)
![\dfrac{4X+6Y+5Z}{40}\leq 8](https://tex.z-dn.net/?f=%5Cdfrac%7B4X%2B6Y%2B5Z%7D%7B40%7D%5Cleq%208)
![\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19](https://tex.z-dn.net/?f=%5Cdfrac%7B2X%2B2Y%2BZ%7D%7B35%7D%2B%5Cdfrac%7B3X%2B4Y%2B6Z%7D%7B35%7D%2B%5Cdfrac%7B4X%2B6Y%2B5Z%7D%7B35%7D%5Cleq%2019)