Answer:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
x
=
0
y
=
0
+
5
y
=
5
Or
(
0
,
5
)
For:
x
=
−
2
y
=
−
2
+
5
y
=
3
Or
(
−
2
,
3
)
We can now plot the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y-5)^2-0.125)((x+2)^2+(y-3)^2-0.125)(y-x-5)=0 [-20, 20, -10, 10]}
Now, we can shade the left side of the line.
graph{(y-x-5) >= 0 [-20, 20, -10, 10]}
Consider the function f(x<span>) = 2 x + 1. We recognize the equation y = 2 x + 1 as the Slope-Intercept form of the equation of a line with slope 2 and y-intercept (0,1). Think of a point moving on the </span>graph<span> of f. As the point moves toward the right it rises.
hope this helps
</span>
Let the second no. be x
-3x = 21 → x = 21/-3 → x = -7
The answer to this problem is neither. To find this you would just plug in each ordered pair into the equation for the x and y values. Then you would compare if they are equal
