I really need help with these two problems ?
1 answer:
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Answer:
a. 54.05 Mpbs.
b. 2.745... standard deviations.
c. The z-score is 2.745....
d. The carrier's highest data speed is significantly high.
Step-by-step explanation:
a. The difference between the highest measured data speed and the mean is 72.6 - 18.55 = 54.05 Mbps.
b. The amount of standard deviations of 54.05 Mbps is equal to this value divided by the standard deviations, so we yield standard deviations.
c. The z-score is equal to the difference between the mean and a data point in standard deviations, so the z-score is 2.745....
d. 2.745... is not between -2 and 2, so the carrier's highest data speed is not insignificant - so it's significantly high.
Answer:
y = 4 sin( 0.5t - ) - 2
y = a sin ( 2t - ) + 2
Step-by-step explanation:
In the first question,
amplitude = 4
Period =
phase shift =
Vertical shift = -2
Angular velocity , w =
Here, w = = 0.5
The general equation of a wave is
y = a sin( wt + ∅ )
Putting above values in the equation,
y = 4 sin( 0.5t - ) - 2
In the second question,
Amplitude is not given so we will take it as a.
time period =
w = 2
Phase shift =
Vertical shift = 2
The equation is
y = a sin ( 2t - ) + 2