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Ratling [72]
3 years ago
9

I really need help with these two problems ?

Mathematics
1 answer:
Annette [7]3 years ago
6 0

Answer:

This dude is a d!(k

Step-by-step explanation:

He deleted my answer and marked this other dude brainliest

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An item that was selling for $72.00 was reduced to $60.00. Find the percent decrease in price. Show all your work.
dsp73
The formula to figure out the percentage increase or decrease is: 
<span>(new - old) / old * 100% </span>

<span>new = 60 </span>
<span>old = 72 </span>

<span>(60 - 72) / 72 * 100% </span>
<span>-12 / 72 * 100% </span>
<span>= -1/6 * 100% </span>
<span>= -0.1666... * 100% </span>
<span>≈ -16.667% </span>

<span>Because it is negative, that's a decrease. </span>

<span>Answer: </span>
<span>A decrease of about 16.7%</span>
8 0
3 years ago
The question is on the picture included
Alexxx [7]
The next step is to draw an arc with center E.

4 0
3 years ago
What does License Ends in 28 days mean?
Ivanshal [37]

I think it means expires. I'm not sure though

4 0
2 years ago
Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is
malfutka [58]

Answer:

m=135000000 Kg

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

\rho=\frac{m}{V}

where \rho is the density, m is the mass and, V is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

V= (length)(heigh)(width).

So for our pool

V= (20)(50)(10).

V= 10000m^{3}.

Our density is in g/mL, so the last thing we need to do before computing the mass is to express the density in Kg/m^{3} (this is because we want our mass in Kg and, we have our volume in m^{3}).

For the density conversion we have to remember that

1000mL = 1L

1L=0.001m^{3}

1000g=1Kg

so

\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g}   =13500\frac{Kg}{m^{3}}.

With this we can finally compute mass:

\rho=\frac{m}{V}

m=\rho*V

m=(13500*10000) Kg

m=135000000 Kg.

4 0
3 years ago
What is the intersection of the sets A=3, 4, 6 14, 19) and B= (1, 3 6, 8,14)?
zhenek [66]

Answer = <em>(3,6,14)</em>

Intersection of sets simply means to list down the numbers that appear in both sets

8 0
3 years ago
Read 2 more answers
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