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2 years ago

|–2| + | 0.6| what is the answer to this question plz help

Mathematics

2 answers:

RUDIKE [14]2 years ago

7 0

2.6 i believe is the answer

Julli [10]2 years ago

6 0

Answer:

$2.6$

Step-by-step explanation:

$2+0.6=2.6\\\text{cancels out because of other signs}$

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sergey [27]

Answer:

the answer is 97 student tickets and 15 adult tickets

Step-by-step explanation:

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2 years ago

How many solutions does this system have?*

sweet-ann [11.9K]

Answer:

1 solution

Step-by-step explanation:

$y = - 3 \\ y = - x - 4 \\ = > - 3 = - x - 4 \\ = > - x - 4 + 3 = 0 \\ = > - x - 1 = 0 \\ = > - x = 1 \\ = > x = - 1$

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2 years ago

Eleanor and her little sister Joanna are responsible for two chores on their family’s farm, gathering eggs and collecting milk.

iris [78.8K]

Answer:

4 dozens

Step-by-step explanation:

Find Eleanor and Joanna's ratio of eggs to milk

Eleanor:

Dozen eggs : gallons of milk

9 : 3

3 : 1

Joanna:

Dozen eggs : gallons of milk

2 : 2

1 : 1

They gather one gallon of milk each which means Joanna has 1 dozen eggs and Eleanor has 3 dozens of eggs.

Total dozen of eggs = 3 + 1 = 4

Therefore, total dozen of eggs the family have per week is 4 dozens.

4 0

2 years ago

Let P=x^2+6 PLEASE SHOW WORK!! 15 POINTS

stellarik [79]

Answer:

Step-by-step explanation:

P = x^2 + 6

$(x^2+6)^2 - 21 = 4x^2 + 24\\(x^2+6)^2 - 4x^2 - 45 = 0$

Solving for 4x^2:

P = x^2 +6

P - 6 = x^2

4(P - 6) = 4x^2

Substitution:

$p^2 - 4p - 24 - 45 = 0\\p^2 -4p - 69 = 0$

4 0

2 years ago

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of

steposvetlana [31]

Cards are drawn, one at a time, from a standard deck; each card is replaced before the next one is drawn. Let X be the number of draws necessary to get an ace. Find E(X) is given in the following way

Step-by-step explanation:

From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26

A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace.

P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13

WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces?

P(AA) = (4/52)(3/51) = 1/221.

WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king?

P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed.

WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the

probability of drawing the first queen which is 4/52.

The probability of drawing the second queen is also 4/52 and the third is 4/52.

We multiply these three individual probabilities together to get P(QQQ) =

P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible.

Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit)

5 0

2 years ago