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3 years ago

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(6x²y³)² 108x⁶y Can someone help me on this one?

1 answer:

Svetradugi [14.3K]3 years ago

7 0

Answer:

oh wow i rlly wish i know the answer to this im sorry

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Question: A book contains 10 photograph , some in color and some in black-and-white. Each

padilas [110]

Answer:

B

Step-by-step explanation:

8 0

3 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

2(3-x)-1.4(5-2x)=2x+5.3

Hitman42 [59]

I think the answer is : x = -5.25

7 0

1 year ago

Read 2 more answers

What is 12 2/3 as an improper fraction

BaLLatris [955]

Answer:

$\dfrac{38}{3}$

Step-by-step explanation:

$12\dfrac{2}{3} =$

$= 12 + \dfrac{2}{3}$

$= \dfrac{12}{1} + \dfrac{2}{3}$

$= \dfrac{12}{1} \times \dfrac{3}{3} + \dfrac{2}{3}$

$= \dfrac{36}{3} + \dfrac{2}{3}$

$= \dfrac{38}{3}$

4 0

3 years ago

Please help on this equation: 7s+20=4s-13. and please if you can, show your work. Thank You!

jonny [76]

7s + 20 = 4s -13
7s - 4s = -13 -20
3s = -33
s = -33/3
s = -11

6 0

3 years ago