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Marat540 [252]
3 years ago
12

Solve the following permutation. 6P3

Mathematics
1 answer:
victus00 [196]3 years ago
4 0
Here, the answer is 120
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The 99% confidence interval for the population mean is 22.96 to 26.64

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Consider the provided information,

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Thus, 1-α=0.99

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Now we need to determine z_{\frac{\alpha}{2}}=z_{0.005}

Now by using z score table we find that  z_{\frac{\alpha}{2}}=2.58

The boundaries of the confidence interval are:

\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

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Here's the break why it is not proportional...

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