S = πr(r + √(h² + r²))
400.2 = 3.14(6)(6 + √(h² + 6²))
400.2 = 18.84(6 + √(h² + 36))
18.84 18.84
21¹⁰⁹/₄₇₁ = 6 + √(h² + 36))
- 6 - 6
15¹⁰⁹/₄₇₁ = √(h² + 36)
231²²¹⁰⁰⁵/₂₂₁₈₄₁ = h² + 36
- 36 - 36
195²²¹⁰⁰⁵/₂₂₁₈₄₁ = h²
14 ≈ h
True, they all have different values !
Answer:
2 hours 30 minutes
Step-by-step explanation:
Step one
Given data
The total distance to be covered= 20miles
Priya runs at a constant speed of 6 miles an hour
Hence Her speed = 6mph
Jada walks at a constant speed of 2 miles an hour
Hence Her speed = 2mph
let the time taken by them to cover the distance be t
Step two:
from speeed= distance/time
distance= speed*time
so
20=6*t+2*t
20= 6t+2t
20=8t
divide both sides by 8
t= 20/8
t=2.5 hours
That is, it wiil take them 2 hours 30 minutes to meet
The reason is because, the distances covered by them must sum up to 20 miles
207 kilograms/ 4 kilograms = 51.75 Which would mean the truck can carry 51 bricks. There's no need to carry 3/4 of a brick.
Answer:
Step-by-step explanation:
1. Symbolically, we get: 62 - 5x < 40
2. y - 7.3 < 3.4. Solve for y by adding 7.3 to both sides, obtaining:
y < 10.7 This is both the 'range' and the 'solution'
3a) 4b = 9b + 45, or -5b = 45, or b = -9
3b) 5a + 10 = 4a - 4
Combining like terms results in a = -14
