X=y-2
2y=5x-17
Substituting for x into the second equation, we find
2y=5(y-2)-17
2y=5y-10-17
-3y=-27
y=9
So x=7
Thus, the two numbers are 7 and 9.
Answer:
$4
Step-by-step explanation:
Answer:
58%
Step-by-step explanation:
10*5=50
7*3=21
21/50 chance to choose inside small rectangle
21/50*2 = 42/100 chance to choose inside small rectangle
100-42=58%
Let
A = event that the student is on the honor roll
B = event that the student has a part-time job
C = event that the student is on the honor roll and has a part-time job
We are given
P(A) = 0.40
P(B) = 0.60
P(C) = 0.22
note: P(C) = P(A and B)
We want to find out P(A|B) which is "the probability of getting event A given that we know event B is true". This is a conditional probability
P(A|B) = [P(A and B)]/P(B)
P(A|B) = P(C)/P(B)
P(A|B) = 0.22/0.6
P(A|B) = 0.3667 which is approximate
Convert this to a percentage to get roughly 36.67% and this rounds to 37%
Final Answer: 37%
Use the depreciation formula.
Where 'p' is the principal value, 'r' is the rate it depreciates, and 'n' is the time. Just plug in what we know:
Simplify by subtracting:
Simplify the exponent:
Multiply:
