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ch4aika [34]
3 years ago
9

What is 15 out of 100 in simplest form

Mathematics
1 answer:
arsen [322]3 years ago
4 0
Use 5 as the lowest common factor and you gt 3/20
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Solve using the standard algorithm <br> 1.03 +0.08
nataly862011 [7]

Answer:

1.11

Step-by-step explanation:

1.03+0.08=1.11

4 0
3 years ago
Find the length indicated. find CE
torisob [31]
Okay, to find length CE, your going to know the value of <em>x</em>. Length BC + CE = BD + DE.
3x+47+x+26=27+x+10
Simplify the equation to get
4x+73=37+x
you can choose one of four ways to continue, but I will choose to subtract x
3x+73=37
Subtract 73 from both sides of the equal sign
3x=-36
divide by 3 on both sides of the equal sign to get the value of x
x=-12

Now, plug in -12 for x in length CE to get -12+26=14
6 0
3 years ago
A dinner plate fits tightly into a box whose square base has a perimeter of 28 inches.What is the circumference of the plate?
ZanzabumX [31]

The diameter of the plate would be equal to the length of a side of the box.

Find the length of the box by dividing the perimeter by 4:

28 / 4 = 7 inches.

The diameter is 7 inches.

Circumference is found by multiplying the diameter by pi:

The exact circumference is 7PI

Using 3.14 for pi, the decimal answer is:

3.14 x 7 = 21.98 inches ( round answer as needed.)

5 0
3 years ago
Without a calculator how would you solve this?
mina [271]

Answer:

the largest number that is less than (2+√3)^6 is 2701

Step-by-step explanation:

\bigstar \ (2+\sqrt{3})^6= \\\\C{}^{0}_{6}2^{6}+C{}^{1}_{6}2^{5}\sqrt{3}^1+C{}^{2}_{6}2^{4}\sqrt{3}^2+C{}^{3}_{6}2^{3}\sqrt{3}^3+C{}^{4}_{6}2^{2}\sqrt{3}^4+C{}^{5}_{6}2^{1}\sqrt{3}^5+C{}^{6}_{6}\sqrt{3}^6

=64+192\sqrt{3}+720 +480\sqrt{3} +540+108\sqrt{3} +27\\=1351+780\sqrt{3}

\bigstar\  (2-\sqrt{3} )^6 =\\\\1351-780\sqrt{3}

\bigstar\  \bigstar\  (2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =\\\\1351+780\sqrt{3}+1351-780\sqrt{3}

\Longrightarrow(2+\sqrt{3} )^6+(2-\sqrt{3} )^6 =2702

\Longrightarrow(2+\sqrt{3} )^6 =2702-(2-\sqrt{3} )^6

0 < \left( 2-\sqrt{3} \right) < 1 \Longrightarrow 0 < \left( 2-\sqrt{3} \right)^{6} < 1 \Longrightarrow-1 < \left( 2-\sqrt{3} \right)^{6} < 0

\Longrightarrow2702-1 < 2702-\left( 2-\sqrt{3} \right)^{6} < 2702+0

\Longrightarrow 2701 < \left( 2+\sqrt{3} \right)^{6} < 2702

8 0
2 years ago
Please answer need fast
agasfer [191]

Answer:

B is the correct ans

please mark brainliest

6 0
2 years ago
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