Answer: -1 usually represents infinity.
Explanation:
It would keep going forever and not be able to stop without manually stopping it.
Answer:
retupmoc
Explanation:
1.) Anwser will be retupmoc
because
public static String mysteryString(String s){
if(s.length() == 1){
return s;
}
else{
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
}
}
In this program input is "computer" . So the function mysteryString(String s) it does
return s.substring(s.length() -1) + mysteryString(s.substring(0, s.length()-1));
so when it enters the first time ??s.substring(s.length() -1) and it will be give you 'r' then it calls the function recursively by reducing the string length by one . So next time it calls the mysteryString function with string "compute" and next time it calls return s.substring(s.length()-1)? + mysteryString(s.substring(0,s.length-1)) so this time it gives "e" and calls the function again recursively . It keeps on doing till it matched the base case.
so it returns "retupmoc".
The answer is true.
Explanation:
The scanner class's methods are the methods in java.util, which allows the user to read values of various types. If the nextLine is issued after a numeric read and the numeric value is at the end of the line, nextLine returns the empty string.
The problem occurs when you click the enter key which is a new line \n character. nextInt() has only the integer but skips the new line \n.
To solve this problem, you have to add the input.nextLine() after reading the int it will consume the \n.
Hence, make input.nextLine(); call after input.nextint(); which reads till end of life.