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lys-0071 [83]
2 years ago
9

Practice 2- digits subtraction 50-18

Mathematics
2 answers:
zheka24 [161]2 years ago
7 0
50 minus 18 is 32 :)
timofeeve [1]2 years ago
5 0
If you're asking what 50 minus 18 is, it's 32. 
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Asap please !
nevsk [136]

Answer:

Maybe, since it's a fair game.

Step-by-step explanation:

8 0
2 years ago
Translate the statement into an algebraic expression or equation.
Alexandra [31]

We want to translate the given statement into an algebraic expression.

The expression is:

d = 0.45*L

---------------------------------

When we have a discount of an X% on a given value V, that discount will be:

D = (X%/100%)*V.

Here we have:

<em>"A </em><em>discount</em><em> of a 45% on the list price L"</em>

The discount will be given by:

d = (45%/100%)*L = 0.45*L

d = 0.45*L

This is the expression we wanted to get.

If you want to learn more, you can read:

brainly.com/question/2736271

4 0
2 years ago
A rectangular painting is 42 centimeters wide and 51 centimeters long. What is the perimeter of this painting?
Alex
186cm
You add all the sides up, so 42+42+51+51 which equals 186cm
6 0
2 years ago
What is 11÷165 as a decimal please answer
LuckyWell [14K]

Answer:

0.066666666

Step-by-step explanation:

also known as 0.06 repeating

6 0
2 years ago
Read 2 more answers
Extreme cold and hot temperatures are known to affect the operation of electronic components. Winter is approaching and you are
Musya8 [376]

Answer:

A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

Test statistic(Z) = 2.31

P-value = 0.0104

Step-by-step explanation:

Step 1

Null hypothesis: The average damaging temperature of nine iPods is 5°F

Alternate hypothesis: The average damaging temperature of nine iPods differs from 5°F

Step 2

Mean=5°F, Sd=3, df=n-1=9-1=8

The t-value corresponding to 8 degrees of freedom and 95% confidence level (5% significance level) is 2.306

Confidence Interval(CI) = (mean + or - t×sd/√n)

CI = (5 + 2.306×3/√8) = 5 + 6.918/2.828= 5+2.45=7.45°F

CI = (5 - 2.306×3/√8) = 5-2.45 = 2.55°F

Z = (sample mean - population mean)/(sd÷√n) = (5-2.55)/(3÷√8) = 2.45/1.061 = 2.31

Step 3

Using the standard distribution table, the cumulative area to the left of Z = 2.31 is 0.9896

P-value = 1 - 0.9896 = 0.0104

Step 4

Conclusion: A 95% confidence interval for the true mean minimum temperature that will damage an iPod is between 2.55°F and 7.45°F

7 0
3 years ago
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