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3 years ago

PLEASE HELP ME 10 POINTS!

Mathematics

2 answers:

steposvetlana [31]3 years ago

6 0

- 17/12 should be the answer.

nirvana33 [79]3 years ago

5 0

4/10

I'm not 100% sure though

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Hey if anyone could help it would be much appreciated

riadik2000 [5.3K]

Answer:

I think it is 0.029

Step-by-step explanation:

I think sorry if its wrong

8 0

3 years ago

Read 2 more answers

Find the balance in the account after the given period.

leva [86]

Substituting our values into the formula we get
$A=4200(1+ \frac{0.042}{12})^1^2^*^2
\\ = 4200(1+0.0035)^2^4
\\ = 4200(1.0035)^2^4
\\ = 4567.37$

7 0

3 years ago

What is 5 4<br> _ divided by _<br> 6 12

Ivanshal [37]

Answer: 5/12

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

One of the roots of the quadratic equation 4mnx^2 – 6m^2x – 6n^2x + 9mn = 0 (m, n ≠ 0) is a)-3m/2n b)3m/2n c)2m/3n d)-2m/3n

maxonik [38]

Answer:

$B.\ \frac{3m}{2n}$

Step-by-step explanation:

Given

$4mnx^2 - 6m^2x - 6n^2x + 9mn = 0\ (m, n \neq 0)$

Required

Calculate one of the root of the equation

$4mnx^2 - 6m^2x - 6n^2x + 9mn = 0$

Factorize

$2mx(2nx - 3m) -3n(2nx - 3m) = 0$

$(2mx - 3n)(2nx - 3m) = 0$

Split equation

$2mx - 3n = 0\ or\ 2nx - 3m = 0$

Make x the subject of formula in both expressions

$2mx = 3n\ or\ 2nx = 3m$

$x = \frac{3n}{2m}\ or\ x = \frac{3m}{2n}$

<em>From the list of given options, one of the roots of the equation is</em> $\frac{3m}{2n}$

4 0

4 years ago

A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose 1/10 degree every 1/4 hour for

klio [65]

Answer:

The rate is $\frac{2}{5}$ degree per hour.

Step-by-step explanation:

Given : A scientist conducted an experiment. Due to chemical reaction, the temperature of a compound rose $\frac{1}{10}$ degree every $\frac{1}{4}$ hour for a limited time.

To find : What was the rate, in degrees per hour that the temperature of the compound rose ?

Solution :

In every $\frac{1}{4}$ hour the temperature of a compound rose $\frac{1}{10}$ degree

To get the rate, in degrees per hour,

In every 1 hour the temperature of a compound rose is

$r=\dfrac{\frac{1}{10}}{\frac{1}{4}}$ degree

$r=\dfrac{4}{10}$ degree/hr

$r=\dfrac{2}{5}$ degree/hr

Therefore, the rate is $\frac{2}{5}$ degree per hour.

5 0

3 years ago