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andre [41]
3 years ago
8

As the pulses interfere destructively there is a point in time when the string is perfectly straight. Which of the following sta

tements is true at this moment? a)The energy of the string is zero. b)The string is not moving either up or down. c)The string has only kinetic energy.
Physics
1 answer:
uysha [10]3 years ago
3 0

According to the statement we can deduce that the resulting amplitude of the wave pulse is zero when there is a destructive interference of two pulses and the chain is straight. At this point the potential energy will be zero, therefore when applying the energy conservation theorem, the potential energy must be equal to the kinetic energy and be conserved. The potential energy will be totally transferred as kinetic energy and therefore that will be the only energy present in the string.

Thus, the option C is correct.

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Projectile A is launched horizontally at a speed of 20. Meters per second from the top of a cliff and strikes a level surface be
miv72 [106K]

consider the motion of projectile A in vertical direction :

v₀ = initial velocity of projectile A in vertical direction = 0 m/s         (since the projectile was launched horizontally)

a = acceleration of the projectile = g = acceleration due to gravity = 9.8 m/s²

t = time of travel for projectile A = 3.0 seconds

Y = vertical displacement of projectile A = height of the cliff = h = ?

using the kinematics equation along the vertical direction as

Y = v₀ t + (0.5) a t²

h = (0) (3.0) + (0.5) (9.8) (3.0)²

h = 44.1 m

4 0
3 years ago
Vector vector a has a magnitude of 29 units and points in the positive y-direction. when vector vector b is added to vector a ,
Nutka1998 [239]
Good morning.

We have:

\mathsf{\overset{\to}{a} = 29\overset{\to}{j}}

Where j is the unitary vector in the direction of the y-axis.

We have that 

\mathsf{\overset{\to}{a}+\overset{\to}{b} = -18\overset{\to}{j}}

We add the vector -a to both sides:

\mathsf{\overset{\to}{b} = -18\overset{\to}{j} -\overset{\to}{a} = -18\overset{\to}{j} -29\overset{\to}{j}}\\ \\ \mathsf{\overset{\to}{b}=-47\overset{\to}{j}}


Therefore, the magnitude of b is 47 units.
5 0
3 years ago
Read 2 more answers
A curve in a stretch of highway has radius R. The road is not banked in any way. The coefficient of static friction between the
adelina 88 [10]

Answer:

maximum possible velocity = \sqrt{ugR}

Explanation:

centripetal acceleration when the  car is going in the circle must be less than the maximum friction for the car to not slip.

centripetal acceleration \frac{mv^{2}}{r}

where v is the velocity of car and r is the radius of circle

maximum friction = umg

where u is the coefficient of static friction.

thereforeumg\geq \frac{mv^{2}}{R}

therefore maximum possible velocity = \sqrt{ugR}

6 0
3 years ago
PLEASE HELP !!!
emmainna [20.7K]

Answer and Explanation:

The answer is <u>D) Alpha and Gamma</u>

Gamma radiation does not cause transmutations.

A <u>transmutation</u> is the <u>conversion of an atom of one element to an atom of another. This generally occurs through nuclear reacting.</u>

There are three main types of radiation: alpha, beta, and gamma. Both beta and alpha decay cause changes to the mass and atomic numbers. This results in a transmutation. Gamma radiation, however, does not.

Gamma radiation is the result of a gamma ray. In essence, the nucleus emits a high-energy proton. This is very penetrating and can only be stopped by aluminum, lead, soil, water, and concrete. This type of radiation does not change the element and, therefore, does not cause a transmutation.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

3 0
3 years ago
A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation x =
abruzzese [7]
I'll tell you how I look at this, although I may be missing something important.

Position = x(t) = 0.5 sin(pt + p/3)

Speed = position' = x'(t) = 0.5 p cos(pt + p/3)

Acceleration = speed' = position ' ' = x ' '(t) = -0.5 p² sin(pt + p/3)

At (t = 1.0),

x ' '(t) = -0.5 p² sin( 4/3 p )

In order to evaluate this, don't I still have to know what 'p' is ? ?

I don't think it can be evaluated with the information given in the question.
6 0
3 years ago
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