Question

A 90 kilogram diver jumped from a cliff. If it takes 2.26 seconds for the diver to hit the water, how high is the cliff?

Answer 1

The height of the cliff will be 25.05 m. The height of the cliff is obtained by the Newton equation of motion.

What is height?

The vertical distance between the object's top and bottom is defined as height. It is measured in centimeters, inches, meters, and other units.

The given data in the problem is;

Mass of diver(m)=90 kilogram

Time period(t)=2.26 sec

Initial velocity (u)=0 m/sec

The height attained by the cliff is;

$\rm H = ut + \frac{1}{2}gt^2 \\\\ H=\frac{1}{2}gt^2\\\\ H= \frac{1}{2}(9.81)(2.26)^2\\\\ H= \frac{1}{2} \times 9.81 \times 5.1076 \\\\ H=25.05 \ m$

Hence, the height of the cliff will be 25.05 m.

To learn more about the height, refer to the link;

brainly.com/question/10726356

#SPJ2

Answer 2

Answer:

3.27 meters

Explanation:

mark brainliest please