The height of the cliff will be 25.05 m. The height of the cliff is obtained by the Newton equation of motion.
<h3>What is height?</h3>
The vertical distance between the object's top and bottom is defined as height. It is measured in centimeters, inches, meters, and other units.
The given data in the problem is;
Mass of diver(m)=90 kilogram
Time period(t)=2.26 sec
Initial velocity (u)=0 m/sec
The height attained by the cliff is;
![\rm H = ut + \frac{1}{2}gt^2 \\\\ H=\frac{1}{2}gt^2\\\\ H= \frac{1}{2}(9.81)(2.26)^2\\\\ H= \frac{1}{2} \times 9.81 \times 5.1076 \\\\ H=25.05 \ m](https://tex.z-dn.net/?f=%5Crm%20H%20%3D%20ut%20%2B%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2%20%5C%5C%5C%5C%20H%3D%5Cfrac%7B1%7D%7B2%7Dgt%5E2%5C%5C%5C%5C%20H%3D%20%20%5Cfrac%7B1%7D%7B2%7D%289.81%29%282.26%29%5E2%5C%5C%5C%5C%20H%3D%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%209.81%20%5Ctimes%205.1076%20%5C%5C%5C%5C%20H%3D25.05%20%5C%20m)
Hence, the height of the cliff will be 25.05 m.
To learn more about the height, refer to the link;
brainly.com/question/10726356
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