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Vinil7 [7]
4 years ago
13

A magnetic field line: U

Physics
1 answer:
olga nikolaevna [1]4 years ago
6 0

Answer:

A magnetic field line or magnetic flux line shows the direction of a magnet's force and the strength of a magnet. The idea of lines of force was invented by Michael Faraday. ... For example, iron filings placed in a magnetic field line up to form lines that correspond to 'field lines'.

I took that at the beginning of the school year!!

click Brainliest if possible!!

Explanation:

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Will mark as BRAINLIEST.......
irinina [24]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

x=4t^3+3t^2-5t+2

Where,

x is in meters and t is in sec

We know that,

Velocity,

v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5

(a) i. t = 2 s

v=12(2)^2+6(2)-5=55\ m/s

At t = 4 s

v=12(4)^2+6(4)-5=211\ m/s

(b) Acceleration,

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6

Pu t = 3 s in above equation

So,

a=24(3)+6\\\\a=78\ m/s^2

Hence, (a) (i) v = 55 m/s (ii) v = 211 m/s and (b) 78 m/s²

6 0
3 years ago
Excluding the noble gas group, how does the number of valence electrons in an element influence its chemical stability?
BabaBlast [244]

Answer:

A. Elements with intermediate numbers of valence electrons are the last chemically stable.

Explanation:

3 0
3 years ago
Read 2 more answers
What might happen if transformers didn’t exist?
Karolina [17]

Answer:

B electricity could not be distributed through power lines to people's homes

7 0
3 years ago
Which of the following best explains how the Ptolemy’s (geocentric) and Copernicus’s (heliocentric) models of the solar system d
TiliK225 [7]

Answer:

The correct answer is c

Explanation:

In these two different models of movement of the planets

Ptolemy raises the Earth as the center of the solar system

In the Copernicus system, it poses the Sun as the center of the solar system.

Copernicu's system was accepted for giving a simpler and more complete explanation of the problem

The correct answer is c

7 0
4 years ago
A proton with mass 1.67*10^-27kg is propelled at an initialspeed of 3.00*10^5m/s directly toward a uranium nucleus 5.00maway. Th
Tresset [83]

Answer:

Explanation:

F = 2.12 x 10⁻²⁶ / x²

Work done by electric field of nucleus

W = ∫ Fdx

= ∫2.12 x 10⁻²⁶ / x² dx

= 2.12 x 10⁻²⁶ ( - 1 / x )

= - 2.12 x 10⁻²⁶ ( 1/5 - 1 / 8 x 10⁻¹⁰ )

= - .265 x 10⁻¹⁶ J

1/ 2 x mv² = .5 x 1.67 x 10⁻²⁷ x 9 x 10¹⁰ - .265 x 10⁻¹⁶

= 7.515 x 10⁻¹⁷ - .265 x 10⁻¹⁶

=( .7515 - .265 )x 10⁻¹⁶

= .4865 x 10⁻¹⁶

.5 x 1.67 x 10⁻²⁷ x v² = .4865 x 10⁻¹⁶

v² = .5826 x 10¹¹

v² = 5.826 x 10¹⁰

v = 2.41 x 10⁵ m /s

b )

Let r be the closest distance

Potential at this point

2.12 x 10⁻²⁶ (  1 / r )

Kinetic energy

= 0

Total energy = 2.12 x 10⁻²⁶ (  1 / r )

Total energy at 5 m

= .5 x 1.67 x 10⁻²⁷ x 9 x 10¹⁰ + 0 ( potential energy at 5 m will be negligible as compared with that near the center )

= 7.515 x 10⁻¹⁷ J

So ,

2.12 x 10⁻²⁶ (  1 / r ) = 7.515 x 10⁻¹⁷

r = 2.12 x 10⁻²⁶ / 7.515 x 10⁻¹⁷

= .282 x 10⁻⁹

= 2.82 x 10⁻¹⁰ m

c ) As electric field is conservative , no dissipation of energy takes place . Hence its speed at 5m on returning back to this point will be same as

3.00 x 10⁵ m /s

7 0
4 years ago
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