Answer:
Step-by-step explanation:
RS Bisects PQ at T Given
PQ bisects RS at T Given
<RTQ = <PTS Vertically opposite Angles
PT = TQ Result of the given bisection
RT = TS Result of the given Bisection
ΔPTS ≡ ΔRTQ SAS. Note that the vertically opposite angles are between the two equal sets of lines.
When we have a function such as h(x) = 2x, and we want to find the value of h at a given x value, we plug in the given number for x. For example, h(3) = 2*3 = 6.
We do the same thing with g(f(7)). In this case we plug 7 into f(x) for x, then plug the result of f(7) into g(x) for x.
f(7) = 15*7 - 12 = 93
g(93) = -15*93^2 + 14*93 - 10 = -128443
Step 1: -4(3x-1) becomes -12x+4
step 2: -12x+4=12-8x
step 3: add 12x to both sides, 4=12+4x
step 4: subtract twelve from both sides -8=4x
step 5: divide by 4, x=-2
Here, √x = 0.5
Squaring on both sides,
(√x)² = (0.5)²
x = 0.25
In short, Your Answer would be Option C
Hope this helps!
