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ANEK [815]
3 years ago
11

Find the equation of the line that passes through point A (1,7) and B (-3, -1)

Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

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Answer:

80%

Step-by-step explanation:

If you divide 52 by 65 you will get a decimal, then multiply by 100% to get the equivalent.

52/65 = 0.8

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jolli1 [7]

Answer:

equation for line:  y = 5/3x -7/3

Step-by-step explanation:

The equation for a linear line is y = mx + c. m is the gradient of the line, also known as slope. So, m = 5/3.

Next we need to find c. Since we know a point the line must intersect, we can sub this into our line equation to get an answer:

(2,1) x=2,y=1

1 = 5/3*2 + c

1 = 10/3 + c

1 - 10/3 = c

3/3 - 10/3 = c

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The final eqaution of the line is: y = 5/3x -7/3

7 0
3 years ago
Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140
Westkost [7]

Answer:

The amount each took home was 20 unit currency.

Step-by-step explanation:

We are given that Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140  apples, went to market and sold all their apples at the same price, and each  received the same sum of money.

Formula  : a \times n + (n - 1), (a + b)\cdot n + (n - 2), (a + 2 \cdot b) \cdot n + (n - 3), (a + 3 \cdot b) \cdot n + (n - 4), (a + 4 \cdot b) \cdot n + (n - 5), (a + 5 \cdot b) \cdot n + (n - 6), (a + 6 \cdot b) \cdot n + (n - 7)

a \cdot n + (n - 1) = 20

(a + b) \cdot n + (n - 2)=40

(a + 2 \cdot b) \cdot n + (n - 3) = 60

(a + 3 \cdot b) \cdot n + (n - 4) = 80

(a + 4 \cdot b) \cdot n + (n - 5) = 100

(a + 5 \cdot b) \cdot n + (n - 6) = 120

(a + 6 \cdot b) \cdot n + (n - 7) = 140

On solving :

n = 7, a = 2, b = 3

So,

2 \times 7 + 6 = 20

5 \times 7 + 5=40

8 \times 7 + 4 = 60

11 \times 7 +  3 = 80

14 \times 7 + 2 = 100

17 \times 7 + 1 = 120

Based on market pricing if groups of apples are sold at 1 unit currency for 7, and extras are sold for 3 unit currency per extra 1, we have the amount :

2×1 + 6×3 = 20

5×1 + 5×3=20

8×1 + 4×3 = 20

11×1 +  3×3 = 20

14×1 + 2×3 = 20

17×1 + 1×3 = 20

20×1 = 20

Therefore, the amount each took home was 20 unit currency.

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