Let 's' represent the amount of sales.
Plan 1:


Plan 2:


Equating the two plans together and solving for the amount of sales,

Collecting like terms,

Divide both sides by 0.08,

Hence, the amount of sales is $8,750.
Answer:
x = -2 y= -8 and 8
Step-by-step explanation:
Since there is an equal number of y's, they cancel out when subtracting. You can put either equation on top. You will get same answer.
<u>To find x:</u>
<u>If you do (3x - 2y = 10) - (5x + 2y = 6),</u> you will get -2x=4. Divide both sides by -2, and get x = -2.
<u>If you do (5x + 2y = 6) - (3x - 2y = 10)</u>, you will get 2x=-4.Divide both sides by 2, and get x = -2.
<u>To find y:</u>
Substitute -2 for x in either equation. It doesn't matter.
<u>For 3(-2) - 2y = 10:</u>
3(-2) - 2y = 10 ––Multiply
-6 - 2y =10 ––Add 6 to both sides to get y alone
-2y = 16 ––Divide by -2
y = -8
<u>For 5x + 2y = 6:</u>
5(-2) + 2y = 6 ––Multiply
-10 + 2y = 6 ––Add 10 to both sides to get y alone
2y = 16 ––Divide by 2
y = 8
46.50 - 19 = 5.50x
We get the 46.50 from her budget and the 19 from the shirt she wants to buy. If we subtract 19 from 46.50, we'll get the amount of money Jasmine can spend on bracelets.
46.50 - 19 = 27.50
She has $27.50 to spend on bracelets. Now, we divide that by 5.50 (the price of a bracelet) to see how many she can buy.
27.50 ÷ 5.50 = 5
Jasmine can buy 5 bracelets.
Hope this helps!
Sin(α+β)=sin(α)cos(β)+cos(α)sin(β)
sin(α-β)=sin(α)cos(β)-cos(α)sin(β)

