Answer:
![v(t) = 8t +5](https://tex.z-dn.net/?f=%20v%28t%29%20%3D%208t%20%2B5)
And that represent the instantaneous velocity at a given time t.
And then we just need to replace t =2 in order to find the instantaneous velocity and we got:
![v(t=2) = 8*2 + 5 = 16+5 = 21](https://tex.z-dn.net/?f=%20v%28t%3D2%29%20%3D%208%2A2%20%2B%205%20%3D%2016%2B5%20%3D%2021)
Step-by-step explanation:
For this case we have the position function s(t) given by:
![s(t) = 4t^2 + 5t+5](https://tex.z-dn.net/?f=%20s%28t%29%20%3D%204t%5E2%20%2B%205t%2B5)
And we can calculate the instanteneous velocity with the first derivate respect to the time, like this:
![v(t) = s'(t)= \frac{ds}{dt}](https://tex.z-dn.net/?f=%20v%28t%29%20%3D%20s%27%28t%29%3D%20%5Cfrac%7Bds%7D%7Bdt%7D)
And if we take the derivate we got:
![v(t) = 8t +5](https://tex.z-dn.net/?f=%20v%28t%29%20%3D%208t%20%2B5)
And that represent the instantaneous velocity at a given time t.
And then we just need to replace t =2 in order to find the instantaneous velocity and we got:
![v(t=2) = 8*2 + 5 = 16+5 = 21](https://tex.z-dn.net/?f=%20v%28t%3D2%29%20%3D%208%2A2%20%2B%205%20%3D%2016%2B5%20%3D%2021)
Answer:
I guess the answer is 5 and 8
The constant of proportionality k is given by y = kx.
In your equation, it would be r = km.
Can you now spot it?