All categories

3 years ago

What is the density of the brown sugar if an 8cm3 block of brown sugar is 12.9 g

Mathematics

1 answer:

julia-pushkina [17]3 years ago

4 0

The answer is 1.6125 g/cm3

You might be interested in

U th th V 3 D F Geometry

loris [4]

Answer:

interesting can i get brainliest

Step-by-step explanation:

8 0

3 years ago

An equilateral ∆ has sides of length 16 cm. Find the length of an altitude.

inn [45]

The length of the altitude is $8\sqrt{3}$

Explanation:

Let ABC be an equilateral triangle.

It has sides of length 16 cm

Let AD be the altitude of the triangle.

We need to determine the length of an altitude.

Let AC = 16 cm and CD = 8 cm

Let us consider the right angled triangle ADC

Using the Pythagorean theorem, we have,

$AC^2=AD^2+DC^2$

Substituting the values, we get,

$16^2=AD^2+8^2$

$256=AD^2+64$

$192=AD^2$

$8\sqrt{3}=AD$

The length of the altitude is $8\sqrt{3}$

5 0

3 years ago

The quotient, of the product of 25 and an unknown number, and 45 is -65.

Vsevolod [243]

25x/45=-65
25x=2925
x=117

I wasn't sure if you wanted a solution

8 0

3 years ago

Mr. Stip bought a new pair of Jordans and 4 new polo shirts. The price of one pair of jordans were double the amount of one polo

Ksenya-84 [330]

9514 1404 393

Answer:

$170

Step-by-step explanation:

If the price of a pair of Jordans is the same as the price of two shirts, the total purchase has a value equivalent to that of 3 Jordans.

pair of Jordans = $510/3 = $170

5 0

2 years ago

Read 2 more answers

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

4 0

2 years ago