Question 11= B
Question 13= C
I don't know how to do question 12
Answer:
(3-2h)^3 + (3-2h)^4 = (3-2h^2)^3 (1 + (3-2h^2))
Area of a triangle= 1/2 (ab) (sin C)
= 1/2 (9 x 11.5) (sin 63.4)
= 46.27
Answer:
Since the balls are drawn with replacement, it means the individual probability remain constant,
I have solved this problem on paper (Figures Attached).
Thanks.
I think x=24 but not sure