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andrew-mc [135]
2 years ago
9

Determine if the equation y = 2(0.45)x represents exponential growth or decay

Mathematics
1 answer:
djverab [1.8K]2 years ago
6 0
We have that
y = 2(0.45)^x

in this problem 
2-----------> is the Coefficient
0.45-------> is the Base
<span>x-----------> is the Exponent

we know that
</span><span>If the base  is less than 1 (but always greater than 0), the function will be exponential decay
</span>It is decay because as x values increase, y values decrease.
<span>0.45 < 1  and 0.45 > 0
therefore

the equation
</span>y = 2(0.45)^x
represents <span>exponential decay
</span>
the answer is
exponential decay<span>

</span>
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½ is the same as 0.5 and the ratio of _____.
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1:2

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A basketball game a team made 52 successful shots they were a combination of 1- and 2- point shots the team scored 86 points in
jasenka [17]

Answer: 15

Step-by-step explanation:

x = one point shots

y = two point shots

 

1) Setup your equations.

 

x + y = 52

x + 2y = 89

 

2) Isolate a variable.

 

x = 52-y

 

3) Plug in.

 

(52-y) + 2y = 89

52 +y =89

y=37

 

4) Solve for x.

 

x = 52 -37

x=15

 

5) Check your answer.

 

15 + 2(37) = 89

15+74=89

89=89

 

37+15 = 52

52=52

x = one point shots

y = two point shots

 

1) Setup your equations.

 

x + y = 52

x + 2y = 89

 

2) Isolate a variable.

 

x = 52-y

 

3) Plug in.

 

(52-y) + 2y = 89

52 +y =89

y=37

 

4) Solve for x.

 

x = 52 -37

x=15

 

5) Check your answer.

 

15 + 2(37) = 89

15+74=89

89=89

 

37+15 = 52

52=52

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2 years ago
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AysviL [449]

Answer:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

Step-by-step explanation:

For this case we have the following value:

R = 0.0498 \frac{Kpa}{Km}

We can convert this first to \frac{Kpa}{m} like this:

R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}

Now we use the fact the the pressure is defined as P =\frac{F}{A}, whre P is the pressure, F the force and A the area, so then Kpa= \frac{KN}{m^2} and then we can replace this:

R=0.0000498 \frac{KN}{m^3}

Now from definition of work we know that W= Fd where W is the work, F the force and d the distance, so then is equivalent KN =\frac{KJ}{m}

And if we replace this into the equation we got:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

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Which algebra expression represents this phase ?
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Answer:

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