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Liono4ka [1.6K]
3 years ago
9

Jeans are reduced from 28.00 to 18.20 during a sale at a department store. What percentage was the original price reduced?

Mathematics
1 answer:
Natali [406]3 years ago
6 0

Answer:

The original price was reduced 35%

Step-by-step explanation:

we know that

Jeans are reduced from $28.00 to $18.20

In this problem

The original price of 28.00 represent 100%

so

using proportion

Find out what percentage represent the difference between the original price and the new price

\frac{28}{100}=\frac{28-18.20}{x}\\\\x=100(9.8)/28\\\\x=35\%

therefore

The original price was reduced 35%

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An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum valu
exis [7]
Take the derivative with respect to t
- w \sin(wt) + \sqrt{8} w cos(wt)
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
0 = -w \sin(wt) + \sqrt{8} w cos(wt)
divide by w
0 =- \sin(wt) + \sqrt{8} cos(wt)
we add sin(wt) to both sides

\sin(wt)= \sqrt{8} cos(wt)
divide both sides by cos(wt)
\frac{sin(wt)}{cos(wt)}= \sqrt{8}   \\  \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\  \\ wt=arctan(2 \sqrt{2)} OR\\ wt=arctan( { \frac{1}{ \sqrt{2} } )
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be

I=cos(2n \pi -2arctan( \sqrt{2} ))
since 2npi is just the period of cos
cos(2arctan( \sqrt{2} ))= \frac{-1}{3} 

substituting our second soultion we get
I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))
since 2npi is the period
I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3}
so the maximum value =\frac{1}{3}
minimum value =- \frac{1}{3}


4 0
3 years ago
COLOR THEME
elena55 [62]
?!?! whaaatt confused lol
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3 years ago
Is 1.5 greater than 3
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Answer:

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Step-by-step explanation:

Given formula:

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8 0
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