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Triss [41]
3 years ago
13

A tailor pays $10.25 per yard for wool and pays $5.75 per yard for cotton. He bought 4.8 yards of cotton and spent a total of $8

5.00 on the
two types of fabric.
How many yards of wool did he buy?
A. 4.1 yards
B. 5.6 yards
C. 6.2 yards
D. 8.2 yards
Mathematics
1 answer:
Leona [35]3 years ago
3 0

Answer:

A. 4.1 yards

Step-by-step explanation:

Multiply $10.25 by 2 because there is 2 fabrics. You would get 20.5 and divide 20.5 from 85.00 and the answer is 4.1.

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sattari [20]
I honestly don’t know but I hope you find the answer to this question soon and have a good night good luck
6 0
3 years ago
Angles: can somebody tell me the angles of X, Y, Z please p.s 25 points if answered correctly
antoniya [11.8K]

Answer:

X=30; Z=80; Y=70

Step-by-step explanation:

The straight lines equal 180 and you subtract 180 to 150 and 180 to 100 to get 30 and 80 and the inside of a triangle is 180 and you subtract 30 and 80 to 180 to get 70.

3 0
3 years ago
A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data
LuckyWell [14K]

Answer:

(25.53, 37.87): 95% CI

(23.59, 39.81): 99% CI

Step-by-step explanation:

The margin of error of a confidence interval is given by:

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

z is related to the confidence level. The higher the confidence level, the higher the values of z, and thus, we wider the confidence interval is.

In this question:

The narrower C.I. is the 95%, and the wider is the 99%. So

(25.53, 37.87): 95% CI

(23.59, 39.81): 99% CI

4 0
3 years ago
Wanna hear something funny I have been asking questions about math all day but none of them have been answered like this is the
scZoUnD [109]

Answer:

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Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A sample of 64 observations has been selected to test whether the population mean is smaller than 15. The sample showed an avera
KengaRu [80]

Answer:

Test statistic = - 0.851063

- 2.520463

Step-by-step explanation:

H0 : μ ≥ 15

H1 : μ < 15

Sample mean, xbar = 14.5

Sample standard deviation, s = 4.7

Sample size = 64

Teat statistic :

(xbar - μ) ÷ (s/√(n))

(14.5 - 15) ÷ (4.7/√(64))

= - 0.851063

The critical value at α = 0.05

Using the T - distribution :

Degree of freedom, df = 64 - 1 = 63

Tcritical(0.05, 63) = 1.6694

Test statistic - critical value

-0.851063 - 1.6694

= - 2.520463

8 0
3 years ago
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