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2 years ago

Help I need the awnser asap

Mathematics

1 answer:

Mrac [35]2 years ago

4 0

Answer:

Is it not just EF?

Step-by-step explanation:

I mean BC is the bottom of the triangle so the corresponding part is just the other triangles bottom which is EF if it was just angle B it'd be just angle E but it's not it's both B and C so it's E and F

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PLEASE HELP PLEASE I NEED IT TODAY

Andrews [41]

Answer:

:) Hope this helps.

Step-by-step explanation:

3 0

3 years ago

Let a and b be roots of x² - 4x + 2 = 0. find the value of a/b² +b/a²

erastovalidia [21]

Answer:

$\dfrac{a}{b^2}+\dfrac{b}{a^2}=10$

Step-by-step explanation:

Given equation: $x^2-4x+2=0$

The roots of the given quadratic equation are the values of x when $y=0$ .

To find the roots, use the quadratic formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=1, \quad b=-4, \quad c=2$

$\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}$

$\textsf{Let }a=2+\sqrt{2}$

$\textsf{Let }b=2-\sqrt{2}$

Therefore:

$\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}$

6 0

2 years ago

Read 2 more answers

Rob is travelling to germany he drives for1 1/2 hours wait for 2 3/4 hours flight lasts 2 1/3 hours how long has he travelled pu

DIA [1.3K]

We add all these mixed numbers together:

1 1/2 + 2 3/4 + 2 1/3

It will be easier to convert the mixed numbers into improper fractions:

3/2 + 11/4 + 7/3

Now we have to find the common denominator which is 12:

18/12 + 33/12 + 28/12 = 79/12 = 6 7/12

The answer is 6 7/12 hours.

7 0

4 years ago

Read 2 more answers

Make a list of 5 numbers with a mean of 12 and a mode of 15. <br><br> Explain if you can

mart [117]

The mean is the average value of the numbers given in the series

The mode is the number that is appears more than any other number given in the series

Step-by-step explanation:

Given challenge is make a list of 5 numbers

The list of 5 number is = 8,10,12,15,15

$Mean value = (8+10+12+15+15)/5 =60/5 = 12$

so required mean is 12 has been computed

Mode = 15 ( the number 12 is appeared in two times 8,10,12,15,15)

Final answer

The required numbers are = 8,10,12,15,15

6 0

3 years ago

The center of a circle lies on the line y = 4x + 1 and is tangent to the x-axis at (−3,0) . What is the equation of the circle i

Hunter-Best [27]

Answer:

$(x+3)^2+(y+11)^2=121$

Step-by-step explanation:

Consider a sketch of the problem as shown in the picture, where:

Blue line is given by y = 4x + 1.
Point B is the center of the circle.
Point A is (-3, 0).

Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.

So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.

Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by

$(x-h)^2+(y-k)^2=r^2$

then with h = -3, k = -11 and r= 11, the equation of our circle is

$(x+3)^2+(y+11)^2=121$

5 0

3 years ago