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3 years ago

I'll mark brainliest! Please help me, i'm desperate for an explanation lol!

Mathematics

1 answer:

borishaifa [10]3 years ago

3 0

Answer:

Question 1: x = -75/38

Question 2: -5/6 X (-5/8) X 6/5 = 5/8

Step-by-step explanation:

Question 1: 3 4/5x - 2 1/2 for x = -10

Given equation is in whole number form so by simplifying we get:

19/5x - 5/2 = -10 (As 5*3 + 4 = 19 and 2*2+1 = 5)

Now Add 5/2 on both sides we get:

19/5x - 5/2 +5/2 = -10 + 5/2

19/5x = -10 + 5/2

Taking LCM we get:

19/5x = (-20+5)/2

19/5x = -15/2

Multiply both sides by 5/19

x = -15/2 * 5/19

x = -75/38

Question 2:

= -5/6 X (-5/8) X 6/5

Multiplying first 2 fractions we get:

= 25/48 X 6/5 ("-" multiplied by "-" gives "+")

25 in numerator will be cancelled from 5 in denominator giving 5
6 in numerator will be cancelled by 48 in denominator giving 8

= 5/8 X 1/1

Multiplicative identity

= 5/8

I hope it will help you!

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Can anyone help me with the slope-intercept form?? sorry it's sideways!!

navik [9.2K]

Answer:

y=5/3x -1

Step-by-step explanation:

you have 2 points: (0, -1) and (3, 4)

slope is the rise/run

so -1-4/0-3

=-5/-3

1 2/3

5 0

3 years ago

A survey recently reported that the mean national annual expenditure for inpatient and outpatient services of all persons over 6

zlopas [31]

Using the z-distribution, it is found that the p-value for this test is of 0.0375.

At the null hypothesis, it is tested if the expenses are the same as the national average, that is, of $5,423. Hence:

$H_0: \mu = 5423$

At the alternative hypothesis, it is tested if it is higher, hence:

$H_1: \mu > 5423$

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 5516, \mu = 5423, \sigma = 979, n = 352$

The value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{5516 - 5423}{\frac{979}{\sqrt{352}}}$

$z = 1.78$

The p-value is the probability of finding a sample mean above $5,516, which is 1 subtracted by the p-value of z = 1.78.

Looking at the z-table, z = 1.78 has a p-value of 0.9625.

1 - 0.9625 = 0.0375

Hence, the p-value for this test is of 0.0375.

A similar problem is given at brainly.com/question/25549474

7 0

3 years ago

Simplify the following surds 45 <------ the 45 is a surd

Anika [276]

I think the answer is 3 route 5
First find a perfect square that goes into 45 in this case 9
Then as it's 9x5 simplify the nine to 3
Hope this helps

8 0

3 years ago

I will give brainliest if you answer

viktelen [127]

The answer is -2.4 -12/5 goes to -2 2/5 or -2.4

3 0

3 years ago

Read 2 more answers

Consider the following two-person zero-sum game. Both players simultaneously call out one of the numbers f2; 3g. Player I wins i

boyakko [2]

Answer:

The pay off matrix (for numbers 1-9) is shown in the attached table.

The value of the game (expected winning per play) = $9.57

The strategy for player II is to call even numbers all the time, which guarantees a winning in every game!

The strategy for player I is to call odd numbers all the time, in case player II calls odd numbers (good luck!)

Step-by-step explanation:

The pay off matrix (for numbers 1-9) is shown in the attached table.

The payoff for player II (even wins) is 775 for 9*9 = 81 possible scenarios.

Thus the value of the game is 775/81 = $9.57 (expected winnings per play)

The strategy for player II is to call even numbers all the time, which guarantees a winning in every game!

The strategy for player I is to call odd numbers all the time, in case player II calls odd numbers (good luck!)

3 0

3 years ago