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3 years ago

Simplify the following surds 45 <------ the 45 is a surd

1 answer:

8 0

I think the answer is 3 route 5
First find a perfect square that goes into 45 in this case 9
Then as it's 9x5 simplify the nine to 3
Hope this helps

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Solve for x.<br> -7 > 13 - 50<br> Enter your answer as an inequa

Svet_ta [14]

-7>-63 because the more negative the number the less the value

6 0

3 years ago

If you is 8 , what is the value of x?

aev [14]

What is the equation???

6 0

3 years ago

Round 122.1587 to the nearest hundredth?

valina [46]

Answer:

100

Step-by-step explanation:

H T U

1 2 2

2 is a num below 5 therefore

2=0

8 0

3 years ago

How do you write 592% as a fraction, mixed number, or whole number in simplest form?

Bumek [7]

In fraction and Mixed number, there the same 5 23/25
Hope it help!

3 0

3 years ago

You want to rent an unfurnished one-bedroom apartment in Boston next year. The mean monthly rent for a random sample of 10 apart

Brilliant_brown [7]

Answer:

90% confidence interval: (2186.53;2881.47)

95% confidence interval: (2118.73;2949.27)

99% confidence interval: (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=2534$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=670$ represent the population standard deviation

n=10 represent the sample size

90% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$

Now we have everything in order to replace into formula (1):

$2534-1.64\frac{670}{\sqrt{10}}=2186.53$

$2534+1.64\frac{670}{\sqrt{10}}=2881.47$

So on this case the 90% confidence interval would be given by (2186.53;2881.47)

95% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$2534-1.96\frac{670}{\sqrt{10}}=2118.73$

$2534+1.96\frac{670}{\sqrt{10}}=2949.27$

So on this case the 95% confidence interval would be given by (2118.73;2949.27)

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$2534-2.58\frac{670}{\sqrt{10}}=1987.37$

$2534+2.58\frac{670}{\sqrt{10}}=3080.63$

So on this case the 99% confidence interval would be given by (1987.37;3080.63)

For the last part is not the best way say : "This interval describes the price of 95% of the rents of all the unfurnished one-bedroom apartments in the Boston area."

The best interpretation is this one: "We are 95% confident that the actual mean for the rents of unfurnished one-bedroom apartments in the Boston area is between (2118.73;2949.27)"

7 0

3 years ago