Answer:
A ) 8.50x + 11 < 24x + 60
B ) 8.50x + 24 < 11x + 60
C ) 11x + 24 < 8.50x + 60
D ) 8.50x + 60 < 11x + 24
Step-by-step explanation:
Option 4 is correct i.e. <span>The volume of the box is increasing at a rate of 192 cm^3/min.
</span>Given : Volume of the rectangular box = x²h
where x is edge and h is height.
The edge and the height are varying with time, therefore, we write,x = x(t)
h = h(t)
dh/dt = -3 and we shall calculate when x = 4, dx/dt = 2 and when h=15
V = x²h dV/dt = (2x × dx/dt × h) + (x² × dh/dt) dV/dt = 2×4×2×15 + (4)^2 ×(-3) dV/dt = 240 - 48
dV/dt = 192
Because dV/dt is positive, hence the volume is increasing
The answer to this question would be =<span><span><span>−<span>x^2</span></span>+<span>26x</span></span>+<span>8 I think. Sorry if it's wrong</span></span>
Oh no my answer i tooooooooooo short ok bye
its not c.
answer- b
