Answer:
Distance to appointment point = 5 miles
Step-by-step explanation:
Let s be the distance to the appointment point,
We have Maria drove to a business appointment at 50mph in the morning.
Time taken in the morning
Her average speed on the return trip in the afternoon was 40 mph.
Time taken in the afternoon
Given that the return trip took 1/4hr longer because of traffic.
That is
Substituting
Distance to appointment point = 5 miles
Answer:
last date of discount period =June 15
cash discount = $215.73
bill or amount = $1402.27
last credit date = July 5
Step-by-step explanation:
A company received an invoice for$1618 dated may 11,terms 2/15 EOM what is the last date of the discount period and last date of credit period answer with formula
a A 2/15 EOM or ending of the month means the buyer receives a cash discount if the amount or bill is paid within a period of 15 days after the end of the month indicated May 11
EOM RESULT in the end of the discount period June 15
Total discount = 2/15 *$1618 = $215.73
Amount or bill to be paid = $1618 - $215.73 = $1402.27 on JUNE 15
last date of credit period the credit period is the period or time the buyer is given to pay the seller That is 20 days after the end of the cash discount period so the credit period last date is JULY 5
When a relationship between two variables is proportional, it means that there is a constant ratio between the two variables. In this case, the answer is yes, there is a proportional relationship between total savings on gas and the number of beverages purchased.
You save $0.20 on gas for every beverage you buy.
Let s=dollars saved on gas, and b=# of beverages purchased
s=.2b
or
s=b/5
Answer:
B. 1. x^6
2. -6a^7
3. r^11
4. x^6
5.a^3b^6
6.x^14
7. 12y^8
8. 55x^4y^6
9. 30m^4n^4
10. 6a^10b^6c^16
C. 1. 40m+60n-810
2. 12am^2 - 8an- 16al^3+4ap
3. 2xmn-3ymn-4zmn
4. 20bx^2-8bx+20b
5. -28xa+4xb-14x
6. y^2 - 4
7. 4x^2 - 16
8. 16b^2 - 4
9. 25a^2-49
10. 9m^2-49
Triangular sequence = n(n + 1)/2
If 630 is a triangular number, then:
n(n + 1)/2 = 630
Then n should be a positive whole number if 630 is a triangular number.
n(n + 1)/2 = 630
n(n + 1) = 2*630
n(n + 1) = 1260
n² + n = 1260
n² + n - 1260 = 0
By trial an error note that 1260 = 35 * 36
n² + n - 1260 = 0
Replace n with 36n - 35n
n² + 36n - 35n - 1260 = 0
n(n + 36) - 35(n + 36) = 0
(n + 36)(n - 35) = 0
n + 36 = 0 or n - 35 = 0
n = 0 - 36, or n = 0 + 35
n = -36, or 35
n can not be negative.
n = 35 is valid.
Since n is a positive whole number, that means 630 is a triangular number.
So the answer is True.
